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3 years ago

Question 1

Chemistry

1 answer:

OLga [1]3 years ago

3 0

Answer: 7 atm

Explanation:

According to Dalton's Law, the total pressure is the sum of all the individual gas pressures

Hence, Ptotal = P1 + P2 + P3

Since, Gas A = 2 atm

Gas B = 1 atm

Gas B = 4 atm

Ptotal = (2 + 1 + 4) atm

Ptotal= 7 atm

Thus, the total pressure of the gas mixture is 7 atmosphere.

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How many grams of aspartame (C14H18N2O5), also known as Nutrasweet, contain 1.98×1021molecules of aspartame?

Umnica [9.8K]

Answer:

0.97 grams

Explanation:

number of molecules=no of moles × Avogadros number

number of moles=nu.of molecules ÷ 6.02×10power23 = 1.98×10power21 ÷ 6.02×10p23=0.0033 mol

mass=nu.of moles× molar mass

molar mass of aspartame=

(14×12)+18+(2× 14.0067n)+(5×16)=294.0134 u

mass = 0.0033 ×294.0134 =0.97 gram

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3 years ago

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Step2247 [10]

Answer:

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3 years ago

Express 0.08010 in exponential notation to the proper significant figures

nataly862011 [7]

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3 years ago

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro

melamori03 [73]

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Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For nickel:

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol$

For the given chemical reaction:

$3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)$

For nickel (II) oxide:

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from $\frac{3}{3}\times 0.252=0.252mol$ of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

$0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g$

For aluminium:

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from $\frac{2}{3}\times 0.252=0.168mol$ of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

$0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g$

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

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3 years ago

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vlada-n [284]

Answer:

a new substance is formed, if heat is formed, color change, the evolution of gas, and bubbles or fizzing

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3 years ago