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Alenkasestr [34]
4 years ago
5

A compound of phosphorus and chlorine contains 3.00grams of phosphorus and 10.3 grams of chlorine. how many grams of phosphorus

would be in a sample of the compound containing 17.2 grams of chlorine?
Chemistry
1 answer:
valentina_108 [34]4 years ago
6 0

Answer:

mass of phosphorus = 5.01 g

Explanation:

Given data:

Mass of chlorine in sample = 10.3 g

Mass of phosphorus in sample = 3.00 g

Mass of chlorine in same sample = 17.2 g

Mass of phosphorus in this sample = ?

Solution:

To solve this problem we will use cross multiplication method.

Mass of phosphorus / mass of chlorine = Mass of phosphorus / mass of chlorine

3.00 g / 10.3 g =  x / 17.2 g

0.29126 × 17.2 g = x

x = 5.01 g

So the sample with 17.2 gram of chlorine will have 5.01 gram of phosphorus in it.

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36.4 g of SnCl2 is dissolved in 135.7 mL of water.
Yuki888 [10]

Answers:

1st: 189.6 g/mol

2nd: 0.1357 L

3rd: 1.41 M

Explanation:

Finding Molar Mass:

SnCl2 = <u>Tin(II) Chloride</u>

Tin has a molar mass of <u>118.71 g/mol</u>

Chloride has a molar mass of <u>35.453 g/mol</u>

Chloride*2 = <u>70.906</u>

<u>118.71 + 70.906 ≈ 189.6 g/mol</u>

Finding Liters of Solution:

L = mL/1000

135.7 mL / 1000 = <u>0.1357</u>

Finding Molarity:

molarity = <u>moles of solute / liters of solution</u>

M = (36.4g /  189.6g) / 0.1357 L = <u>1.41 M</u>

Hope this helped ;)

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