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Alenkasestr [34]
3 years ago
5

A compound of phosphorus and chlorine contains 3.00grams of phosphorus and 10.3 grams of chlorine. how many grams of phosphorus

would be in a sample of the compound containing 17.2 grams of chlorine?
Chemistry
1 answer:
valentina_108 [34]3 years ago
6 0

Answer:

mass of phosphorus = 5.01 g

Explanation:

Given data:

Mass of chlorine in sample = 10.3 g

Mass of phosphorus in sample = 3.00 g

Mass of chlorine in same sample = 17.2 g

Mass of phosphorus in this sample = ?

Solution:

To solve this problem we will use cross multiplication method.

Mass of phosphorus / mass of chlorine = Mass of phosphorus / mass of chlorine

3.00 g / 10.3 g =  x / 17.2 g

0.29126 × 17.2 g = x

x = 5.01 g

So the sample with 17.2 gram of chlorine will have 5.01 gram of phosphorus in it.

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equal to 1

Explanation:

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A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

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Answer:

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