Answer:
Subtract
1
1
1
from both sides of the equation
2
+
1
=
1
1
2
+
1
−
1
=
1
1
−
1
2
Simplify
3
Divide both sides of the equation by the same term
4
Simplify
Solution
=
5
Step-by-step explanation:
Answer: A
Step-by-step explanation:
- Open circle means that x does not equal that number. For example, the open circle on C is on 8, so that shows x is not equal to 8.
- Closed circle means that x does equal that number. For example on A, there is a closed circle on 8, so x could equal 8.
First, we need to solve the equation.
- Subtract 200 frim 1200 -> 125x ≥ 1000.
- Divide 125 from 1000 to isolate the x -> x ≥ 8
So, that means x is bigger than or equal to 8.
Answer:
150 degrees
Step-by-step explanation:
Let's start off by looking at what we are working with in this specific problem:
We can see that we are looking at 2 angles, angle L and angle M, that add up to a total of 180 degrees (aka a straight line)
Now that we know that, we also have to keep is mind that angle L + angle M = 180 degrees.
Now that we've got all of that out of the way, let's set up a simple algebraic equation:
angle L + angle M = 180
We also know that angle L is 30 degrees so let's add it into the equation we have just created:
30 + angle M = 180
We now know that 30 plus angle M (whatever it might be) is equal to 180 so in order to solve this problem we have to do some simple subtraction.
180 - 30 = angle M
Now we are left with:
150 degrees = angle M
The number of permutations of the 25 letters taken 2 at a time (with repetitions) is:

The number of permutations of the 9 digits taken 4 at a time (with repetitions) is:

Each permutation of letters can be taken with each permutation of digits, therefore the total number of possible passwords is:
The right answer for the question that is being asked and shown above is that:
Two numbers have a sum of 71 and a difference of 37
x + y = 71
x - y = 37
So in order to get the two numbers, here it is:
x + y = 71
x - y = 37
------------
2x = 108
x = 54
y = 71 - 54
y = 17
<span>So the two numbers are 54 and 17</span>