Recall your d = rt, distance = rate * time.
now, if the boat has a speed of say "b", and the current has a speed of say "c", when the boat is going upstream, is not really going "b" fast, is going " b - c " fast, because the current is eroding speed from it, going upwards.
And when the boat is going downstream, is not going "b" fast either, because the current is now adding to speed to it, so is really going " b + c " fast.
The time it took one way, is the same time it took back, 4 hours each way.
thus

what's the speed of the boat? well, 5 + c = b.
Step-by-step explanation:
37x + 41y = 70 --- R¹
41x + 37y = 86 --- R²
R¹ + R² : 78x + 78y = 156
78(x + y) = 156
x + y = 2 --- R³
R¹ - R² : -4x + 4y = -16
4(y - x) = -16
y - x = -4 --- R⁴
R³ + R⁴ : 2y = -2
y = -1
R³ - R⁴ : -2x = -6
x = 3
Step-by-step explanation:
Y=-4x+3
2x+3y=19
2x+3(-4x+3)=19
2x-12x+9=19
-10x=10
X=-1
y=-4*(-1)+3=4+3=7
x=-1 y=7
To solve the problem we use the compound formula given by:
A=p(1+r/100)^n
where:
A=future amount:
p=principle
r=rate
A=1000000, r=11.6%, n=40
plugging the value in the formula we get:
1000000=p(1+11.6/100)^40
solving for p we get:
1000000=80.6432p
p=12400.300
rounding to the nearest 1000 we get
p=$12000
Answer:
<span>A.) 12,000</span>