Question

PLEASE HELP!!!!! Factor completely 16x8 − 1

Answer 1

Answer:

the answer is (2x² - 1)(2x² + 1)(4x^{4} + 1 )

Step-by-step explanation:

Answer 2

Answer:

see explanation

Step-by-step explanation:

This is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

16$x^{8}$ = ( 4$x^{4}$ )² ⇒ a = 4$x^{4}$

1 = 1² ⇒ b = 1

Hence

16$x^{8}$ - 1

= (4$x^{4}$ )² - 1²

= (4$x^{4}$ - 1)(4$x^{4}$ + 1)

4$x^{4}$ - 1 ← is also a difference of squares and factors as

(2x² - 1)(2x² + 1)

Thus

16$x^{8}$ - 1

= (2x² - 1)(2x² + 1)(4$x^{4}$ + 1 )