Answer:
9/16 Kinked tail, normal growth
3/16 Kinked tail, obese growth
3/16 normal tail, normal growth
1/16 normal tail, obese growth
Explanation:
Kinked tail (K) is dominant over normal tail (k) and normal growth (N) is dominant over obese growth (n). Two mice that are heterozygous for both traits (KkNn) are crossed:
KkNn x KkNn
offspring:
<em>9/16</em><em> K_N_ - Kinked tail, normal growth</em>
<em>3/16</em><em> K_nn - Kinked tail, obese growth</em>
<em>3/16</em><em> kkN_ - normal tail, normal growth</em>
<em>1/16</em><em> kknn - normal tail, obese growth</em>
(See the attached image for the Punnet's square analysis)
I believe the answer is the first one you listed,
Hope this helps..
The question is the following :
<span>What is the best evidence to prove that Irene was heterozygous for hemophilia?
A) Alice carried the recessive allele.
B) Alexandra carried the recessive allele.
C) Frederick carried the recessive allele.
D) Waldemar carried the recessive allele.
The correct answer is A
In the pedigree, marked with blue are the carriers of the X recessive allele ( they have one X that has the mutation and the other that doesn't).
Alice was Irene's' mother, and since both Alice and iIrene have the allele, it is safe to conclude that Irene inherited the recessive allele from Alice.</span>
I believe the answer is b.