All categories

3 years ago

How many times does 20 go into 190

2 answers:

5 0

- - Solve:

Multiply.

20*x=190

But here is the thing.

It can only go in "9" times because if we did 20*9=180, we cant add 20 more or we go over.

Therefore 20 can only go in 190, 9 times.

mihalych1998 [28]3 years ago

4 0

It will go in it 9 times cause 9*20=180

You might be interested in

PLEASEEEEE HELPPPPP !!!!!!!!!!! I will mark Brianliesttttt !!!!!!!!!!!!!!!

ipn [44]

Answer:

D. m<RST = 2(m<TSU)

Step-by-step explanation:

Given that m<RST = 76°, m<RSU = 48°, and m<TSU = 38°, this implies that:

SU is an angle bisector of angle RST. Thus,

m<RST is twice the measure of <RSU or <TSU.

Therefore, the only option that is correct is:

D. m<RST = 2(m<TSU)

3 0

3 years ago

If cos⁡ x=−45, and 180° < x < 270°, what is tan⁡(2x)?

iVinArrow [24]

$Tan2x =\frac{-24}{7}$

<u>Step-by-step explanation:</u>

Here we have , cos x = -4/5 ( corrected as given -45 which is not possible ) ,

180° < x < 270° i.e. in third quadrant . We need to find tan⁡(2x) . Let's find out:

⇒ $Tan\alpha = \frac{sin\alpha }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(cos\alpha)^2} }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(\frac{-4}{5})^2} }{\frac{-4}{5} }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{1-(\frac{16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{(\frac{25-16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}(\frac{3}{5}) }$

⇒ $Tan\alpha = \frac{-3}{4}$ , since in third quadrant . $Tan\alpha = \frac{-3}{4}$ remains same .

Now , $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2(\frac{-3}{4})}{1-(\frac{-3}{4})^{2}}}$

⇒ $Tan2x = \frac{-3}{2}(\frac{16}{7})$

⇒ $Tan2x =\frac{-24}{7}$

Therefore, $Tan2x =\frac{-24}{7}$ .

5 0

4 years ago

Find the value of "k" such that 1/2 is a root of 2x^2+11x=-k

trapecia [35]

The value of k is -6

Step-by-step explanation:

The general form of the quadratic equation is y = ax² + bx + c

The roots of the equation is the values of x when y = 0
ax² + bx + c = 0, is used to find the roots

∵ 2x² + 11x = -k

- Add k to both sides

∴ 2x² + 11x + k = 0

∵ The roots of the quadratic equations is the values of x when y = 0

∵ $\frac{1}{2}$ is a root of the equation

- Substitute x by $\frac{1}{2}$ in the equation above to find k

∵ 2( $\frac{1}{2}$ )² + 11( $\frac{1}{2}$ ) + k = 0

∴ 2( $\frac{1}{4}$ ) + $\frac{11}{2}$ + k = 0

∴ $\frac{1}{2}$ + $\frac{11}{2}$ + k = 0

- Add the like terms

∵ $\frac{1}{2}$ + $\frac{11}{2}$ = $\frac{12}{2}$ = 6

∴ 6 + k = 0

- Subtract 6 from both sides

∴ k = -6

The value of k is -6

Learn more:

You can learn more about the quadratic equations in brainly.com/question/8196933

#LearnwithBrainly

5 0

3 years ago

P(×)= x(2x + 1)- 6x-3 <br>Factorize p(×)

kherson [118]

Step-by-step explanation:

P(X)=2x²-5x-3 is in the form ax²+bx+c

Using quadratic equation

x={-b±√(b²-4ac)}/2a

x=3,-1/2

4 0

3 years ago

Can u put 0.5,0.41 and 3/5 in least to greatest

baherus [9]

0.41, 0.5, 3/5 is the order

4 0

3 years ago