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Murrr4er [49]
3 years ago
11

If you are designing a force multiplying system with two pneumatic cylinders. Your system should increase the force by a multipl

e of 4. What should you do? O decrease the area in the second cylinder O increase the area in the second cylinder
Physics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

decrease the area in the second cylinder

Explanation:

In a two-cylinders pneumatic system, the pressure exerted on the first cylinder is equal to the pressure on the second cylinder:

p_1 = p_2

We can rewrite the pressure as product between force (F) and area (A) of the cylinder:

F_1 A_1 = F_2 A_2

In this system, the output force should be 4 times the input force:

F_2 = 4 F_1

Substituting into the previous equation, we get:

F_1 A_1 = 4 F_1 A_2\\A_2 = \frac{A_1}{4}

This means that the area of the second cylinder must be 1/4 of the area of the first cylinder, so the correct answer is

decrease the area in the second cylinder

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The answer is C

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A man holds a child on his shoulders while watching a football match. How many work has he done if the game lasts for 2 hours? ​
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very interesting and amazing question u had asked but i get it...

Answer

  • work done is given by

W = Force × Displacement

  • but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
  • there for W= F×0 =0
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<u>More</u><u> </u><u>examples</u>

  • a person standing straight and lifting weight
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hope it helped u buddy

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3 years ago
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When the temperature of an ideal gas is increased, the pressure also ________
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<h2>Answer: increases  </h2><h2 />

Explanation:  

The expression for an Ideal Gas is:  

P.V=n.R.T  

Where:  

P is the pressure of the gas  

V is the volume of the gas  

n the number of moles of gas  

R is the gas constant  

T is the absolute temperature of the gas  

As we can see, there is a <u>direct proportional relation between the temperature and the pressure</u>, which means that if the temperature increases the pressure of the gas increases as well.

However, it is important to note this is fulfilled if and only<u> if the volume of the container where the ideal gas is, remains constant.</u>

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The work done on the block by the spring as it accelerates the block is 4kx².

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Let initial distance is x.

It was compressed three times farther and then the block is released, new distance is 3x.

The work done in compressing the spring is given by :

W=\dfrac{1}{2}k(x_2^2-x_1^2)

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\W=\dfrac{1}{2}k((3x)^2-x^2)\\\\W=\dfrac{1}{2}k((9x^2-x^2)\\\\W=\dfrac{1}{2}k\times 8x^2\\\\W=4kx^2

So, the work done on the block by the spring as it accelerates the block is 4kx².

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