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Murrr4er [49]
3 years ago
11

If you are designing a force multiplying system with two pneumatic cylinders. Your system should increase the force by a multipl

e of 4. What should you do? O decrease the area in the second cylinder O increase the area in the second cylinder
Physics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

decrease the area in the second cylinder

Explanation:

In a two-cylinders pneumatic system, the pressure exerted on the first cylinder is equal to the pressure on the second cylinder:

p_1 = p_2

We can rewrite the pressure as product between force (F) and area (A) of the cylinder:

F_1 A_1 = F_2 A_2

In this system, the output force should be 4 times the input force:

F_2 = 4 F_1

Substituting into the previous equation, we get:

F_1 A_1 = 4 F_1 A_2\\A_2 = \frac{A_1}{4}

This means that the area of the second cylinder must be 1/4 of the area of the first cylinder, so the correct answer is

decrease the area in the second cylinder

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Frank does 2400J of work in climbing a set of stairs. If he does the work in 6 seconds, what is his power output?
timurjin [86]
Power = Work Done / Time taken

         Where Work Done is Joules, and Time is in Seconds, Power is in Watts

            = 2400 J / 6 seconds

            = 400 Watts

The power output is 400 Watts.
4 0
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Sue and Jenny kick a soccer ball at exactly the same time. Sue’s foot exerts a force of 75.9 N to the north. Jenny’s foot exerts
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Answer:

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3 years ago
A bookcase has a base of 1 m long and 0.5 m wide. It has a mass of 300kg. Find the pressure it exerts on the floor in kPa.
Snezhnost [94]
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4 0
3 years ago
A 5kg bag falls a verticle height of 10m before hitting the ground.
g100num [7]

Answer:

u = 7m {s}^{ - 1}

Explanation:

We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:

me(1) = me(2)

where me(1) is mechanical energy while on h=10m

and me(2) is mechanical energy while on the ground

Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)

Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.

DynamicE(2) is equal to zero since it's touching the ground

Using that info we have

m \times g \times h   =   \frac{1}{2}  \times m \times u {}^{2} \\

we divide both sides of the equation with mass to make the math easier.

9.8 \times 10 =  \frac{1}{2}  \times u {}^{2}  \\  \frac{98}{2}  = u {}^{2}  \\ u { }^{2} = 49 \\ u = 7

7 0
4 years ago
if a man hits a golf ball (0.2 kg) which accelerates at a rate of 20 m/s squared. what amount of force acted on the ball?
kkurt [141]

F = ma

We have mass = 0.2kg

and acceleration = 20 m/s^2

So..

F = (0.2)(20)

F = 4 N

6 0
3 years ago
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