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Lapatulllka [165]
3 years ago
8

Using the method of dimension, derive an expression for the velocity of sound waves. assume that the velocitu depends on:

Physics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

v = K √(E / ρ)

Explanation:

Modulus of elasticity has units of N/m², or kg/m/s².

Density has units of kg/m³.

Velocity has units of m/s.

If we divide modulus of elasticity by density, we can eliminate kg:

E / ρ = [kg/m/s²] / [kg/m³]

E / ρ = [m²/s²]

Taking the square root gets us units of velocity:

√(E / ρ) = [m/s]

Multiply by the constant K:

v = K √(E / ρ)

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Answer:

112.23 m

Explanation:

Displacement is the final position minus the initial position.

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Answer:

Explanation:

a )

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c )

Let x be the required distance.  

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160 x 1.5 + 740 x 3 x / 5 + .4 x 900 x 4  = 900 x 3  ( .4 x 900 is the maximum friction possible )

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x = 2.3  m

so man can go upto 2.3 at which maximum friction acts .

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According to the rule of ( n1 sin theta1 = n2 sin theta2 )

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