I'm not sure if that's what you mean, but the difference between 6010 and 5060 is 950, so to find a number in a halfway between them I divided 950 by 2 (which is 475) and added it to 5060 (or substracted from 6010 - it's the same). Next I added the same number (475) to 6010. So finally it would like like this:
6,485 ; 6,010 ; 5,535 ; 5,060
Answer:
500
Step-by-step explanation:
510=x+.21x-.19x
510=(1+.21-.19)X
510=1.02X
X=510/1.02
X=500
X is 7 more than y
x>y then
difference betwen squares is 161 so
x=7+y
and
x²-y²=161
so
x=7+y
sub that for x in other equation
(7+y)²-y²=161
y²+14y+49-y²=161
14y+49=161
minus 49 both sides
14y=112
divide both sides by 14
y=8
sub back
x=7+y
x=7+8
x=15
the numbers are 15 and 8
Hi, thank you for posting your question here at Brainly.
This problem could be solved using the Law of Cosines, since we are given with the three sides. The equation goes,
b^2 = a^2 + c^2 - 2accosB. Substituting,
24^2 = 7^2 + 25^2 - 2(7)(25)cosB
Then B = 73.7 degrees. Therefore sinB or sin(73.7) = 0.96.
