Question

Find the minimum sample size required to estimate the population proportion. Margin of error: 0.024; confidence level: 95%; p and q unknown?

Answer 1

Answer:

1667

Step-by-step explanation:

(Margin of Error)² = (z × 0.5)²/n

Where n = number of samples

Minimum number of samples formula = (z × 0.5)²/ (Margin of Error)²

From the above question:

Margin of Error = 0.024

z = z score of a 95% confidence interval = 1.96

Minimum number of samples

= (1.96 × 0.5)²/(0.024)²

= 0.9604/(0.024)²

= 1667.3611111

Approximately to the nearest whole number = 1667

Therefore, the minimum number of samples is 1667