Answer:
For a height of 66 inches, Z = 0.65.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The average height was about 64.3 inches; the SD was about 2.6 inches.
This means that
66 inches:
The z-score for a height of 66 inches is:
For a height of 66 inches, Z = 0.65.
Answer:
36
Step-by-step explanation:
Answer:
33
Step-by-step explanation:
10+10+13=33
Answer:
c. 0.778 < p < 0.883.
Step-by-step explanation:
The formula for confidence interval for proportion =
p ± z score × √p(1 - p)/n
p = x/n
n = 195, x = 162
z score for 95% confidence Interval = 1.96
p = 162/195
p = 0.8307692308
p ≈ approximately equal to = 0.8308
0.8308 ± 1.96 × √0.8308 × (1 - 0.8308)/195
0.8308 ± 1.96 ×√0.8308 × 0.1692/195
0.8308 ± 1.96 × √0.0007208788
0.8308 ± 1.96 × 0.0268491862
0.8308 ± 0.052624405
Confidence Interval
= 0.8308 - 0.052624405
= 0.778175595
Approximately = 0.778
= 0.8308 + 0.052624405
= 0.883424405
Approximately = p
0.883
Therefore, the confidence interval for this proportion = (0.778, 0.883) or option c. 0.778 < p < 0.883