$18. Multiply 30 by 0.4 and subtract that value from 30 to get the price after the percentage taken away.
When you factor the equation...
r^2-4r-77
r^2+7r-11r-77
r(r+7)-11(r+7)
(r-11)(r+7) so each parenthetical term is a dimension.
Note that r>11 though for any possible real solution.
Add 2 to both sdies
now if we can facor, then if
xy=0 then x and/or y=0
note:xy=x times y and x(y) =x times y
x^2+3x+2=0
what 2 number multiply to get 2 and add to get 3
the numbers are 2 and 1
(x+2)(x+1)=0
set them to zero
x+2=0
subtract 2
x=-2
x+1=0
subtract 1
x=-1
x could be -1 or -2
x=-2, or -1
Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
It can be the last one, 827 over 1120
Hope that helps
