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nikitadnepr [17]
3 years ago
7

Prokaryotic flagella has the same internal structure as eukaryotic flagella.

Biology
2 answers:
Zinaida [17]3 years ago
5 0

The internal structure of prokaryotic flagella is the same as the internal structure of eukaryotic flagella. Prokaryotic cells do not contain endoplasmic reticulum, Gold bodies, mitochondria, plastids, or membrane-bound vesicles.

Alex3 years ago
4 0

Answer:

No, they do not have the same internal structure.

Explanation:

Prokaryotes lack the presence of a nucleus and a cell wall. The size and complexity of the ribosomes and how the cells reproduce are different in prokaryotes and eukaryotes. In eukaryotic cells, the ribosomes are bigger, more complex and bound by a membrane.

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A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
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The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
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