It took Peter 3 hours to drive to his friend in Connecticut when he was driving with the average speed 54 mph. How much time wil
l the way back take if Peter drives with the average speed 60 mph?
1 answer:
The distance is the same. So the two conditions (driving there and driving back) can be equated.
There
t = 3 hours
d = d
r = 54 mph
Back
t = ?
d = d
r = 60 mph
Basic Formula
d = r * t
Solution
54 * 3 = 60 * t Combine the left side
162 = 60 * t Divide by 60 on both sides
162 / 60 = t Combine
2.7 hours = time coming back.
0.7 hours = 60 * 0.7 = 42 which is in minutes.
2 hours and 42 minutes. Answer
You might be interested in
Answer:
Attached is the image of the solution . cheers
Answer:
-8y^2+9y-45
Step-by-step explanation:
symbolab.com
Just plug in an easy number for "x" and solve. Then see if the second problem is really greater that the first
Answer:
x = 34
Step-by-step explanation:
Angles are supplementary:
x + 7 + 4x + 3 = 180
5x + 10 = 180
5x = 170
x = 34
Answer:
x+74=180
x=180-74
x=106
x=4y+22
106-22=4y
84/4=y
21=y
y=21
Step-by-step explanation: