Answer: b. segment TX = 16 m.
B, the first differences are not the same , that proves it is not linear. The second set of differences are the same this shows it is a quadratic function.
The expression
can be used to find the coordinate of Point B. Option C is correct.
Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.
<h3>What is the equation?</h3>
The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.
Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,

now put the value in the formula.

Thus, expression
can be used to find the coordinate of Point B. Option C is correct.
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The value of b is -16 and the value of ac is 60 after comparing with the standard equation.
<h3>What is a quadratic equation?</h3>
Any equation of the form
where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:

We have a quadratic function:
= 3x² - 16x + 20
On comparing with standard function:
b = -16
a = 3
c = 20
ac = 3(20) = 60
Thus, the value of b is -16 and the value of ac is 60 after comparing with the standard equation.
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answer :- x+x² hope you understand