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3 years ago

What mass of H2SO4 would be required to react with 0.75 mil NaOH

Chemistry

1 answer:

77julia77 [94]3 years ago

8 0

Answer:

36.75 grams of sulfuric acid will be required.

Explanation:

Moles of sodium hydroxide = 0.75 mol

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :

$\frac{1}{2}\times 0.75 mol=0.375 mol$ sulfuric acid

Mass of 0.375 moles of sulfuric acid:

0.375 mol × 98 g/mol = 36.75 g

36.75 grams of sulfuric acid will be required.

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I need help with this packet

Anna11 [10]

Q1. An inorganic compound is a compound where the main constituent or substance is not that of Carbon but predominantly other elements, such as I, N etc. An organic compound is one where the main substituent or main element, the element found in much greater amounts would be Carbon.

Q2. Water is considered a very good solvent, because of its ability to dissolve well with mostly all other polar compounds, and produce ions from those ionic compounds.

A. Hydrogen atoms
B. Oxygen atom.

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3 years ago

What is the proper value for C in the above table. A. 28 B. 30 C. 32 D. 65

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Answer:

Explanation:

electron = atomic number - charge(if the charge is positive and addition if the charge is negative)

electron = 30 - 2

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3 years ago

Select the mixture which is capable of tolerating addition of a strong acid without altering the pH? a.) 1.0 M HCl, 1.0 M NaCl b

wlad13 [49]

Answer:

d.) 1.0 M HNO2, 1.0 M NaNO2

Explanation:

A buffer is a mixture that is capable of tolerating addition of a strong acid or base without altering the pH substantially.

A buffer is the mixture of a WEAK ACID AND ITS CONJUGATE BASE or a WEAK BASE AND ITS CONJUGATE ACID

In the problems:

a) HCl is a strong acid and NaCl a salt. NO buffer

b) NH3 is a weak base and NaCL a salt. NO buffer

c) HF is a weak acid and NaCl a salt. NO buffer.

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3 years ago

. Citric acid, which can be obtained from lemon juice, has the molecular formula C6H8O7. A 0.250-g sample of citric acid dissolv

marysya [2.9K]

Answer:

3 acidic hydrogens per molecule of citric acid

Explanation:

In a sample of 37.2 mL(0.0372 L) of 0.105 mol/L of NaOH, will have:

n = 0.105x0.0372 = 0.0039 mol of NaOH

The dissociation of NaOH will give the same number of moles of Na⁺ and OH⁻.

The molar mass of citric acid is:

C: 12g/mol x 6 = 72 g/mol

H: 1g/mol x 8 = 8g/mol

O: 16 g/mol x 7 = 112 g/mol

192 g/mol

So, 0.250g of the acid has

n = mass/molar mass

n = 0.250/192

n = 0.0013 mol.

To be neutralized, it will be necessary 0.0039 mol of acidic hydrogens to react with the 0.0039 mol of OH⁻.

The dissociation reaction of one molecule of the acid will give the stoichiometry:

1 mol of acid ----------------------- x mol of acidic hydrogens

0.0013 mol --------------------------- 0.0039

For a simple direct three rule:

0.0013x = 0.0039

x = 3 acidic hydrogens per molecule of citric acid.

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4 years ago

2 examples of when scientists used space probe technology to find out more about comets.

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