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Burka [1]
3 years ago
11

This question deals with common misconceptions about what Hardy-Weinberg equilibrium (HWE) is. In peas, flower color is controll

ed by a single Mendelian locus with two alleles, R and r. RR plants have red flowers, rr have white flowers, and Rr have pink flowers. Let p equal frequency of R alleles and q equal frequency of r alleles. In the pea population under study, p = 0.50 and q = 0.50. You count the plants for their flower colors and find the following numbers: Red: 40 Pink: 20 White: 40 Total = 100 Which one of the following statements is true:a. We know that the pea population is in HWE at this locus because p + q = 1.b. We know that the pea population is in HWE at this locus because p and q are equal.c. We know that the pea population is in HWE at this locus because the homozygotes are in equal numbers.d. We know that the pea population is in HWE because when we plug p and q into the HWE formula, we find that p2 + 2pq + q2 = 0.25 + 0.50 + 0.25 = 1.e. None of the above.
Biology
1 answer:
butalik [34]3 years ago
7 0

Answer:

I cant understand this question. Can u help?

Explanation:

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Answer:

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Explanation:

  • Due to splitting of the population,
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  • The sub-population of rodents formed in Island C are C1 and C2.
  • In case of Island B, each of the B1 and B2 sub-populations that got split from each other developed certain mutations that were necessary for them to adapt to the particular diverse environment each of them were exposed to, through the period of 50,000 years. These mutations were so varied that reproductive isolation was generated between them that resulted in each of them to develop into different species.Hence, speciation happens here and B1 and B2 are incapable of inter-breeding.
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Explanation:

4 0
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