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3 years ago

Hey can you please help me posted picture of question:)

Mathematics

2 answers:

polet [3.4K]3 years ago

4 0

The given trinomial can be factored using the factorization method.
x² - 2x - 24
The middle term should be written is such a way that the sum of two terms is equal to the middle one and their product should be equal to the product of first and third term. So the above expression can be written as
= x² -6x + 4x - 24
= x(x-6) + 4(x-6)
= (x-6)(x+4)
Thus, (x-6)(x+4) is the factored form of the polynomial.
So the correct answer is option B

MaRussiya [10]3 years ago

4 0

Your answer will be choice B: to prove this we can multiply the two binomials:
(x - 6)(x + 4) = x² + 4x - 6x - 24 = x² - 2x - 24

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I need help 5th grade

Trava [24]

6 5/6 just subtract 2 from the whole (8)

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3 years ago

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4/3x + 1/6x = 36 (solve for x please help I have no idea what it is!!!!!!!

ElenaW [278]

Answer:

x = 24

Step-by-step explanation:

$\frac{4}{3}$ x + $\frac{1}{6}$ x = 36

Make the denominator the same by multiplying the first fraction by 2 to make both denominators 6.

$\frac{8}{6}$ x + $\frac{1}{6}$ x = 36

Now we can calculate the numerators and keep the denominators the same.

$\frac{9}{6}$ x = 36

Find x.

$\frac{6}{6}$ x = $\frac{6}{9}$ × 36

x = 24

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2 years ago

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nekit [7.7K]

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3 years ago

Write the expression 44(4–7)(4) using a single exponent.

Ghella [55]

<h3>The given expression as single exponent is:</h3>

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

$4^4 \times 4^{-7} \times 4$

In exponents,

When the base is same, exponents can be added

Which means,

$a^m \times a^n = a^{m+n}$

Therefore,

$4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}$

Thus the given expression as single exponent is:

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

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3 years ago

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Show all work and reasoning

Natalija [7]

Split up the interval [2, 5] into $n$ equally spaced subintervals, then consider the value of $f(x)$ at the right endpoint of each subinterval.

The length of the interval is $5-2=3$ , so the length of each subinterval would be $\dfrac3n$ . This means the first rectangle's height would be taken to be $x^2$ when $x=2+\dfrac3n$ , so that the height is $\left(2+\dfrac3n\right)^2$ , and its base would have length $\dfrac{3k}n$ . So the area under $x^2$ over the first subinterval is $\left(2+\dfrac3n\right)^2\dfrac3n$ .

Continuing in this fashion, the area under $x^2$ over the $k$ th subinterval is approximated by $\left(2+\dfrac{3k}n\right)^2\dfrac{3k}n$ , and so the Riemann approximation to the definite integral is

$\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n$

and its value is given exactly by taking $n\to\infty$ . So the answer is D (and the value of the integral is exactly 39).

8 0

3 years ago