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andrey2020 [161]
3 years ago
5

How much longer, to the nearest minute, would it take to travel 290 miles at 60mph versus 70 mph.

Mathematics
2 answers:
Mashutka [201]3 years ago
8 0
If you traveled at 60mph and wanted to go to a place 290mi away, it would take 4.83 hours
(about 4 hours and 50 minutes)

but, if you traveled at 70mph and wanted to go to a place 290 miles away, it would take 4.14 hours
(about 4 hours and 8 minutes)

so, it would take about 42 minutes longer to travel at 60mph
velikii [3]3 years ago
3 0
So using the equation distance = velocity * time
we get distance/velocity = time
60 MPH: 290/60 = 4.83333 Hours
60 MPH: 290/70 = 4.1429 Hours

Difference between them:
4.8333 - 4.1429 = 0.69 Hours, then multiply that by 60 and you get
41 Minutes.

Hope this helped!
*psst it would help if you gave me brainliest answer, I'm close to ranking up :) Thanks!
You might be interested in
What is the equation of the line that is parallel to the line 5x 2y = 12 and passes through the point (−2, 4)? y = – five-halves
Oduvanchick [21]

Answer:

The answer is

y =  -  \frac{5}{2} x - 1

Step-by-step explanation:

If two equations are parallel it means that both their gradients are equal. We were given the equation:

5x +  2y = 12

in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:

5x + 2y = 12 \\ 2y = 12 - 5x \\  \frac{2y}{2}  =  \frac{12}{2}  -  \frac{5}{2} x \\ y = 6  -  \frac{5}{2} x \: \\ or \: \\ y =   - \frac{5}{2} x + 6

Therefore the gradient of the parallel line with points (-2, 4) is also -5/2

y = mx + c \\ 4 =  - \frac{ 5}{2} ( - 2) + c \\ 4 =  \frac{10}{2}   + c \\ 4 = 5 + c \\ 4 - 5 = c \\

c =  - 1 \\ hence \: the \: equation \: for \: the \: \\  parallel \: line \: is \\  \: y =  -  \frac{5}{2} x  - 1

8 0
2 years ago
At a quick-lunch counter, 3 pretzels and 1 soda cost
NeX [460]

Answer:

I really did try man ;-;

Step-by-step explanation:

8 0
3 years ago
Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square
N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is \frac{x^2}{10} + \frac{y^2}{15} = 1

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

  • Directrices at x = ±2
  • Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1

So, we have:

\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1

Evaluate

\frac{x^2}{10} + \frac{y^2}{15} = 1

Hence, the equation of the hyperbola is \frac{x^2}{10} + \frac{y^2}{15} = 1

Read more about hyperbola at:

brainly.com/question/3405939

#SPJ1

6 0
2 years ago
NEED HELP ASAPPPPPPPPP
Nookie1986 [14]

Answer:

A  = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

5 0
2 years ago
Use substitution to solve the<br> following system of equations.<br> - 4y - 5x = 30 AND x= y + 3
IRISSAK [1]

Answer:

The solution to the system of equations is y = -5 and x = -2.

Step-by-step explanation:

The question tells us to use substitution to solve the system.  This means that the given value for x (in terms of y) should be substituted into the other equation.  This is modeled below:

-4y - 5x = 30

-4y - 5(y+3) = 30

Next, we should use the distributive property to simplify the left side of the equation.

-4y -5y - 15 = 30

The next step is to combine like terms on the left side of the equation.

-9y - 15 = 30

Then, we can add 15 to both sides of the equation.

-9y = 45

Finally, we can divide both sides of the equation by -9.

y = -5

To find the value for x, we substitute in the value we just found for y into either of our original equations.

x = y + 3

x = -5 + 3

x = -2

Therefore, the correct answer is y = -5 and x = -2.

Hope this helps!

3 0
3 years ago
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