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pogonyaev
3 years ago
8

if a certain number x is doubled, the result is less than or equal to 12. find the range of values of the number​

Mathematics
1 answer:
ki77a [65]3 years ago
4 0

Answer:

2x≤12

2x/2 ≤12/2

x≤6

therefore x=6

x+x

6+6=12

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The length of the longer leg of a right triangle is 4 inches more than twice the length of the shorter leg. the length of the hy
Serjik [45]

The Pythagorean's Theorem for our situation would look like this:

shortleg^2+longleg^2=hypotenuse^2

So let's call the short leg s, the long leg l and the hypotenuse h. It appears that all our measurements are based on the measurement of the short leg. The long leg is 4 more than twice the short leg, so that expression is l=2s+4; the hypotenuse measure is 6 more than twice the short leg, so that expression is h=2s+6. And the short leg is just s. Now we can rewrite our formula accordingly:

s^2+(2s+4)^2=(2s+6)^2

And of course we have to expand. Doing that will leave us with

s^2+4s^2+8s+8s+16=4s^2+12s+12s+36

Combining like terms we have

5s^2+16s+16=4s^2+24s+36

Our job now is to get everything on one side of the equals sign and solve for s

s^2-8s-20=0

That is now a second degree polynomial, a quadratic to be exact, and it can be factored several different ways. The easiest is to figure what 2 numbers add to be -8 and multiply to be -20. Those numbers would be 10 and -2. Since we are figuring out the length of the sides, AND we know that the two things in math that will never EVER be negative are time and distance/length, -2 is not an option. That means that the short side, s, measures 10. The longer side, 2s+4, measures 2(10)+4 which is 24, and the hypotenuse, 2s+6, measures 2(10)+6 which is 26. So there you go!

6 0
3 years ago
What is the slope of the line that passes through the points (-9, -8)((−15,−16)? Write your answer in simplest form.
alexandr402 [8]

Answer:

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope=\dfrac{4}{3}

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:  

Slope = ?

Solution:

Slope of Line Segment AB is given as

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope(AB)=\dfrac{4}{3}

4 0
3 years ago
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drek231 [11]
The original side length was 12m therefore the perimeter was 36m. 12/4 is 3 so the perimeter is now 9, and the difference between them is 27.
4 0
3 years ago
Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi
miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

Solve:

c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}

Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

Parabola passes through the point (-8,1), so

1=a\cdot (-8)^2-7\\ \\64a-7=1

Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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