"Increased" means to add.
"Quotient" is a total of a division problem.
"A number" means the unknown.
This is our problem: 3 + 6 / N
First of all, solve the second parenthesis: if we raise a product to a certain power, it is the same as raising each factor to that power:
![(4x)^3 = 4^3\cdot x^3 = 64x^3](https://tex.z-dn.net/?f=%20%284x%29%5E3%20%3D%204%5E3%5Ccdot%20x%5E3%20%3D%2064x%5E3%20)
So, the expression becomes
![5x^3\cdot 64x^3](https://tex.z-dn.net/?f=%205x%5E3%5Ccdot%2064x%5E3%20)
Now, we multiply the numeric parts:
![5\cdot 64 = 320](https://tex.z-dn.net/?f=%205%5Ccdot%2064%20%3D%20320%20)
and the literal part:
![x^3\cdot x^3 = x^{3+3} = x^6](https://tex.z-dn.net/?f=%20x%5E3%5Ccdot%20x%5E3%20%3D%20x%5E%7B3%2B3%7D%20%3D%20x%5E6%20)
So, the answer is ![320x^6](https://tex.z-dn.net/?f=%20320x%5E6%20)
11x + y = -11
subtract 11x from both sides
y = -11x - 11
this expresson and polynomial can not be factored with rational numbers
Step-by-step explanation:
tan(2pi) = 0
tan(a + b) = (tan(a) + tan(b))/ (1 - tan(a) * tan(b))
tan(theta + 2pi)
= tan(theta) + tan(2pi) / 1 - (tan(theta) * tan(2pi))
= tan(theta) + 0 / 1 - tan(theta) * 0
= tan(theta) / 1
= tan(theta)