Answer:
Step-by-step explanation:
IF it is a SYMMETRIC kite
CB = CD
x + 4 = 2x - 1
x - x + 4 + 1 = 2x - x - 1 + 1
5 = x
AB = AD
x + 3 = 3x - y
5 + 3 = 3(5) - y
8 = 15 - y
y = 7
Given:
The point 
divides the line segment joining points 
and 
.
To find:
The ratio in which he point P divides the segment AB.
Solution:
Section formula: If a point divides a segment in m:n, then the coordinates of that point are,
Let point P divides the segment AB in m:n. Then by using the section formula, we get
On comparing both sides, we get
Multiply both sides by 4.
It can be written as
Therefore, the point P divides the line segment AB in 1:5.
Answer:
your answer would be D
Step-by-step explanation:I really hope you get it right <3 : )
Answer:
-4/3
Step-by-step explanation:
Slope: (y2-y1)/(x2-x1)
(-5-3)/(-3+9) = -8/6 = -4/3
The slope is -4/3
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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