Answer:
Step-by-step explanation:
Letting "a" and "c" represent the costs of adult tickets and child tickets, the problem statement gives us two relations:
3a +5c = 52
2a +4c = 38
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We can solve this system of equations using "elimination" as follows:
Dividing the first equation by 2 we get
a +2c = 19
Multiplying this by 3 and subtracting the first equation eliminates the "a" variable and tells us the price of a child ticket:
3(a +2c) -(3a +4c) = 3(19) -(52)
c = 5 . . . . . . collect terms
a +2·5 = 19 . . substitute for c in the 3rd equation above
a = 9 . . . . . . subtract 10
One adult ticket costs $9; one child ticket costs $5.
Answer:
giyi
Step-by-step explanation:
Answer:

Step-by-step explanation:

<span>3. Two isosceles right triangles
Every square has 4 right angles, so each triangle will have one right triangle, which makes the triangles, right triangles.
They are isosceles because all sides of the square are the same, though the diagonal is not.
Hope this helps :)
</span>
Answer:
x =53.85
Step-by-step explanation:
Let x be the original price
If the price is 22% of, you will pay 100% -22% = 78%
x * 78% = 42
Change to decimal form.
78x = 42
Divide each side by .78.
78x/.78 = 42/.78
Rounding to the nearest cent
x =53.85