Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
<h3>
Answer: 9</h3>
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Work Shown:
a = unknown = leg #1
b = 12 = leg #2
c = 15 = hypotenuse
Plug those values into the pythagorean theorem and solve for 'a'
a^2 + b^2 = c^2
a^2 + (12)^2 = (15)^2 .... substitution
a^2 + 144 = 225
a^2 = 225 - 144 ... subtracting 144 from both sides
a^2 = 81
a = sqrt(81) .... applying square root to both sides
a = 9
Answer: Slope=-2
Step-by-step explanation:
2x - 5y = 11. (4, a). x = 4, y = a
Substituting into 2x - 5y = 11
2(4) - 5(a) = 11
8 - 5a = 11
-5a = 11 - 8
-5a = 3
a = 3/-5 = -3/5 =- 0.6
Other coordinate = -3/5 = -0.6
Answer:
B = 145°
Explanation:
Sorry but m∠C > 90° how could it be 35° ?
However if you still need an answer:
B = 180 - C
B = 180 - 35
B = 145°
