Question

The distance between point (-4,6) and (3,-7)

Answer 1

Disatnce bewteen (x1,y1) and (x2,y2) is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$


so disatnce between (-4,6) and (3,-7) is
$D=\sqrt{(-4-3)^2+(6-(-7))^2}$
$D=\sqrt{(-7)^2+(6+7)^2}$
$D=\sqrt{49+(13)^2}$
$D=\sqrt{49+169}$
$D=\sqrt{218}$

the disatnce is √218 units or aprox 14.7648 units