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Anna35 [415]
3 years ago
13

What two numbers can add to 4 but multiple to -12

Mathematics
1 answer:
olasank [31]3 years ago
7 0

Answer:

<em>Numbers: 6 and -2</em>

Step-by-step explanation:

<u>Equations</u>

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

x+y=4\qquad\qquad [1]

x.y=-12\qquad\qquad [2]

Solving [1] for y:

y=4-x

Substituting in [2]

x(4-x)=-12

Operating:

4x-x^2=-12

Rearranging:

x^2-4x-12=0

Solving with the quadratic formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

With a=1, b=-4, c=-12:

\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}

\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}

\displaystyle x=\frac{4\pm 8}{2}

The solutions are:

\displaystyle x=\frac{4+ 8}{2}=6

\displaystyle x=\frac{4- 8}{2}=-2

This confirms the preliminary results.

Numbers: 6 and -2

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