The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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Answer:
75°
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 6 , then
sum = 180° × 4 = 720°
let x be the sixth angle, then sum and equate to 720°
150 + 100 + 80 + 165 + 150 + x = 720
645 + x = 720 ( subtract 645 from both sides )
x = 75
The sixth interior angle is 75°
Answer:
9
Step-by-step explanation:
I dont know if i did this right but here
x1 = 9.5 y1 = 0
It is 15x because you multiply 3 and 5 and keep your x with it
