If 64ᵃ⁺ᵇ = 32 ᵃ⁺²ᵇ, then a=?

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

5 0

Answer:

64^(a+b)= 32^(a+2b)

<=>(2^6)^(a+b) = (2^5)^(a+2b)

<=>2^(6a+6b) = 2^(5a+10b)

=> 6a + 6b = 5a + 10b

=> a = 4b

Hope this helps!

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