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uysha [10]
3 years ago
15

You are selling concessions at a local swim meet. Hot dogs are being sold for $1.00 and soda is being sold for $0.50. At the end

of the day you made $150. Let x represent the number of hotdogs sold and y represent the number of and sodas sold at the swim meet.
-Using the Standard Form, identify the y-intercept of the graph and explain how the y-intercept relates to the number of hot dogs and sodas sold.
Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

Step-by-step explanation:

Let's set up an equation in standard form.

x + 0.5y = 150

0.5y = -x + 150

y = -2x + 300

The y-intercept is 300. This means that when 0 hot dogs were sold, 300 sodas were sold.

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Step-by-step explanation:

the formula to calculate a circumference is

x \times \pi

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a.

ca = 6 \times 22 \div 7 \\  = 44 \div 7

b.

cb  = 7 \times 22 \div 7 \\  = 154 \div 7 \\  = 22

c.

cc \:  = 4 \times 22 \div 7 \\  = 88 \div 7

hope I helped

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3 years ago
Between which two numbers on the number line is B?
Vanyuwa [196]

Answer:

C. Between 4 and 5.......

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3 years ago
Read 2 more answers
There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Find the numbers.
Pani-rosa [81]

There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19

<h3><u>Solution:</u></h3>

Given that, There are two numbers whose sum is 64.  

Let the number be a and b in which a is bigger.

Then, a + b = 64 ------ eqn (1)

The larger number subtracted from 4 times the smaller number gives 31.  

4 x b – a = 31  

4b – a = 31 ----- eqn (2)

We have to find the numbers.

So, from eqn (2)

a = 4b – 31

Subatitute a in (1)

4b – 31 + b = 64

On solving we get

5b  = 64 + 31  

5b = 95

b = 19

So, b = 19, then eqn 1

a + 19 = 64

On simplification,

a = 64 – 19

a = 45  

Hence, the two numbers are 45 and 19

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4 years ago
Cellular phone service is available for $35 per month for 1118 minutes. What is the monthly cost per minute? Round your answer t
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Answer:

Step-by-step explanation:

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7 0
4 years ago
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

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Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
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