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snow_tiger [21]
4 years ago
10

Helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Furkat [3]4 years ago
4 0

Answer:

B.

The middle line is the median

Hope this helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppps

Step-by-step explanation:

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At a bargain store.Tanya bought 5 items that each cost the same amount. Tony bought 6 items that each cost the same amount, but
Ray Of Light [21]

(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...

... 5x = 6(x -1.75)

(B) Subtract 5x, simplify and add the opposite of the constant.

... 5x -5x = 6x -6·1.75 -5x

... 0 = x -10.50

... 10.50 = x

(C) 5x = 5·10.50 = 52.50

... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value

(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.

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3 years ago
If the point A is translated 5 units up and 10 units to the left, find the location of the resulting point A' ?
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What is 8(5x - 3y)=
Monica [59]

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40x-24y

You simplify through distribution

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I have sons but no daughter ,each of my sons has twice as many brothers as he has children . each of my sons has same no of chil
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Step-by-step explanation:

keeping track of family relations can be difficult. If Edna marries your mother’s uncle Charlie, what should you call her? If your father’s cousin’s daughter just had a baby boy, how should you two be introduced? Who is your “great great aunt”, and how can you find your “first cousin twice removed”? Fortunately, a bit of mathematical logic can clarify who should be called what, and why – and even measure the degree of genetic similarity between different relatives.

7 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
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