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sweet-ann [11.9K]
2 years ago
15

What are the mean and mode of the following data set? 59 16 57 46 58 21 36 41 23 64 20 66 40 51 28 46 a. mean: 43.5, mode: 46 b.

mean: 42, mode: 46 c. mean: 43.5, mode: 42 d. mean: 46, mode: 42
Mathematics
1 answer:
Dvinal [7]2 years ago
6 0

Answer:

\boxed{ \bold{ { \boxed{ \sf{mean \:  =  \: 42 \: , \: mode = 46}}}}}

Option B is the correct option.

Step-by-step explanation:

Given data:

59 , 16 , 57 , 46 , 58 , 21 , 36 , 41 , 23 , 64 , 20 , 66 , 40 , 51 , 28 , 46

Σx ( sum of the items ) = 672

N ( total number of items ) = 16

<u>Finding</u><u> </u><u>the</u><u> </u><u>mean</u>

\boxed{ \sf{mean =  \frac{sum \: of \: the \: items}{total \: number \: of \: items}}}

\longrightarrow{ \sf{ \frac{672}{16} }}

\longrightarrow{ \sf{42}}

Mean = 42

<u>Finding</u><u> </u><u>the</u><u> </u><u>mode</u>

In the given data , 46 has the highest frequency.

So, mode = 46

Hope I helped!

Best regards! :D

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Step-by-step explanation:

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An important tool in archeological research is radiocarbon dating, developed by the American chemist Willard F. Libby.3 This is
Radda [10]

Answer:

Q(t) = Q_o*e^(-0.000120968*t)

Step-by-step explanation:

Given:

- The ODE of the life of Carbon-14:

                                       Q' = -r*Q

- The initial conditions Q(0) = Q_o

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Find:

The expression for Q(t).

Solution:

- Assuming Q(t) satisfies:

                                       Q' = -r*Q

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                                      dQ / Q = -r .dt

- Integrate both sides:

                                       Ln(Q) = -r*t + C

- Make the relation for Q:

                                       Q = C*e^(-r*t)

- Using initial conditions given:

                                       Q(0) = Q_o

                                       Q_o = C*e^(-r*0)

                                      C = Q_o    

- The relation is:

                                       Q(t) = Q_o*e^(-r*t)

- We are also given that the half life of carbon is t = 5730 years:

                                       Q_o / 2 = Q_o*e^(-5730*r)

                                        -Ln(0.5) = 5730*r

                                        r = -Ln(0.5)/5730

                                        r = 0.000120968          

- Hence, our expression for Q(t) would be:

                                       Q(t) = Q_o*e^(-0.000120968*t)                                    

7 0
3 years ago
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svlad2 [7]
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2 years ago
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Answer:

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Anyways,

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150 = 3x

x = 50

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