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vivado [14]
2 years ago
10

Solve and graph the inequality below. PLEASE HELP​

Mathematics
1 answer:
Nata [24]2 years ago
7 0

Answer:

x>12

Step-by-step explanation:

its x is greater than 12

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Determine algebraically whether the function is even, odd, or neither even nor odd.
m_a_m_a [10]
For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x)  [No Relation]

(-x)^n = x^n   for n -> even
(-x)^n = -x^n  for n -> odd
In your example:

f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1  ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x   (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x)  [between the bracket was the original fn]

f(x) = - f(-x)   
so the function is odd also called symmetric about the origin
7 0
3 years ago
Given f(x)=e^-x^3 find the vertical and horizontal asymptotes
Aleonysh [2.5K]

Given:

f\mleft(x\mright)=e^{-x^3}

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}

Thus, y = 0 is the horizontal asymptote for the given function.

5 0
1 year ago
2. Solve the equation.<br> (50 Points)<br> * =<br> + 9 = 30<br> Enter your math answer
barxatty [35]

Answer:

x= 42

Step-by-step explanation:

x/2+9=30

x+18=60

x=60-18

x= 42

5 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form: (1,6) and (2,3) are on the line
s344n2d4d5 [400]

Step-by-step explanation:

eqn of line : y = mx+ c

m = slope or gradient

c = y-intercept.

Lets take (1,6) = (x1,y1) and (2,3) = (x2,y2)

m \:  =  \frac{y1 - y2}{x1 - x2}  \\  =  \frac{6 - 3}{1 - 2}  \\ =  \frac{3}{ - 1}  \\  =  - 3

Substitute x = 1 and y = 6 into equation,

6 = ( - 3)(1) + c \\ 6 =  - 3 + c \\ c = 6 + 3 \\  = 9

Therefore substituting m and c value, equation of line is

y =  - 3x + 9

5 0
2 years ago
Reggie and jay go for a walk morning.reggie walks 2 1/4 miles. Jay walks 1 3/8 miles less than Reggie. What is the total distanc
jek_recluse [69]
Jay walks 2 1/4 miles which if you double it so the denominators are e same for both 2 1/4 and 1 1/8 then your answer will be 18/8 (Jay) and 9/8 (Reggie). Meaning that Reggie walks have the distance Jay walks.
7 0
3 years ago
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