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podryga [215]
3 years ago
11

A random variable x x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a rand

om sample of size n = 36 n=36 and find a sample mean of ¯ x = 98 x¯=98 . What is a 95% confidence interval for the mean of x x ?
Mathematics
1 answer:
Paul [167]3 years ago
8 0

Answer:

95% Confidence Interval: (94.08,101.92)    

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 98

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = 12

95% Confidence Interval:

Formula:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

98 \pm 1.96(\dfrac{12}{\sqrt{36}} ) = 98 \pm 3.92 = (94.08,101.92)

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Answer:

c

Step-by-step explanation:

3 0
3 years ago
Simplify the following expression 4x + 3t - 2x- 4
allochka39001 [22]

Answer:

2x + 3t - 4

Step-by-step explanation:

Hi,

To simplify the expression, we must combine like terms. To start, let's combine all of the x-values.

4x + 3t - 2x - 4

When we combine 4x and -2x we get 2x.

2x + 3t - 4

We can't combine anything else. They don't have the same variables and 4 doesn't even have a variable, so 2x + 3t -4 is the simplified expression.

I hope this helps :)

4 0
3 years ago
Could I get some help on these please? Will give points.
Zielflug [23.3K]

Answer:

X=-4, Y=22, idk about the CBD

Step-by-step explanation:

4y+2=90 degrees

subtract 2 on both sides you would get

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i would subtract 3x first so i can get

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then subtract 6 on both sides so you would have

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6 0
3 years ago
4/25 of the purchases were stuffed animals. 10/21 of them were bears. What fraction of the purchases were stuffed bears?
Bess [88]
Let's name all the purchases "x"

so \frac{4}{25}of them were stuffed animals, and out of that \frac{10}{21} were bears.

to get the results we have to multiply the fraction of bears by the fraction of the stuff animals:

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and this is the answer!






4 0
3 years ago
What is the range of g(x) = 3|x − 1| − 1? A. (-∞, 1] B. [-1, ∞) C. [1, ∞) D. (-∞, ∞)
AVprozaik [17]

Answer:

B. [-1, ∞).

Step-by-step explanation:

g(x) = 3|x − 1| − 1

When x = 1  g(x) = 3(0) - 1 = -1.

As all negative vales of x will give positive values of  |x - 1| then  g(x) = -1 is its minimum value. The graph will be shaped like a letter V with the vertex at (1,-1).

Therefore the range is  [-1, ∞).

6 0
3 years ago
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