1. 5 x 5
2. 7 x 28
3. 90 divided by 70
4. 40 divided by 5.
Hope this helps. #I'm11
<h2>1210 cubic feet</h2>
Step-by-step explanation:
Initial dimensions of the storeroom were
length,
width and
height.
The room is in the shape of a cuboid. Volume of a cuboid =
, where
are the length, width and height of the cuboid.
So, Volume of storeroom initially = 
Finally, the length was increased to
and width to
.
Final volume of storeroom = 
Increase in volume = 
∴ 1210 cubic feet of storage was added.
Answer:
The first three terms of the series are 8, 10 and 12. The number of terms is 12 to make the sum 228.
Step-by-step explanation:
The series is defined as

Put n=1.

Put n=2.

Put n=3.

The first three terms of the series are 8, 10 and 12.
It is an arithmetic series. The first terms is 8 and the common difference is

The sum of n terms of an arithmetic series is
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![288=\frac{n}{2}[2(8)+(n-1)2]](https://tex.z-dn.net/?f=288%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%288%29%2B%28n-1%292%5D)
![288=\frac{2n}{2}[8+n-1]](https://tex.z-dn.net/?f=288%3D%5Cfrac%7B2n%7D%7B2%7D%5B8%2Bn-1%5D)
![288=n[n+7]](https://tex.z-dn.net/?f=288%3Dn%5Bn%2B7%5D)




Equate each factor equal to zero.

The number of terms can not be negative, therefore the value of n must be 12.
Answer:
No
Step-by-step explanation:
9=5(-5)-4
9=-10-4
9=-14
The answer is B, Because f + e = c, a2 + b2 = c2.