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tangare [24]
3 years ago
8

You push against a steamer trunk with a force of 800 n at an angle alpha with the horizontal . the trunk is on a flat floor and

the coefficient of static friction between the trunk and floor is 0.55. the mass of the trunk is 87 kg. what is the largest value of alpha that will allow you to move the trunk?
Physics
1 answer:
galina1969 [7]3 years ago
6 0
The formula for this problem that we will be using is:
F * cos α = m * g * μs where:F = 800m = 87g = 9.8
cos α = m*g*μs/F= 87*9.8*0.55/800= 0.59 So solving the alpha, find the arccos above.
α = arccos 0.59 = 54 ° is the largest value of alpha
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3 years ago
A student pushes on a crate with a force of 100 N directed to the right. What force does the crate exert on the student?
sattari [20]

Answer:

The Force exerted on the student by crate will be 100 N.

Explanation:

As per the given Question student is trying to push the crate in right direction with the force of 100N.

And we know that, Newton's third law states that every action has equal and opposite reaction.

So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.

6 0
2 years ago
The same mass, with a new string, is whirled in a vertical circle of the same radius about a fixed point. Find the magnitude of
Masteriza [31]

Answer:

256.3 N

Explanation:

Throughout the motion of the mass in the circular motion, the resultant of the Tension in the string and the weight of the body gives the net force (centripetal force) that is responsible for the acceleration of the mass in a circular motion.

At the top of the vertical circle of the motion of the mass, the tension is directed downwards towards the centre of the circle and the weight also is directed downwards towards the earth.

Net force = ma = T + W

ma = T + mg

But a = (v²/r) for circular motion,

(mv²)/r = T + mg

m = 2.31 kg

v = 7.77 m/s

r = 0.500 m

g = acceleration due to gravity = 9.8 m/s²

(2.31×7.77²)/0.5 = T + (2.31×9.8)

278.923 = T + 22.638

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Hope this Helps!!!

7 0
2 years ago
a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration?
Dmitrij [34]

Answer:

a=200\ m/s^2 and t = 0.5 s

Explanation:

Given that,

Mass of the object, m = 90 gram = 0.09 kg

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Speed, v = 16 m/s

We need to find the object acceleration. On the circular path, acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{1.28}\\\\a=200\ m/s^2

So, the object's acceleration is 200\ m/s^2.

Let t is time it will take to complete the around. Speed is given by :

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So, time to cover one complete round is 0.5 s.

8 0
2 years ago
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