· free fall is any motion of a body where gravity is the only forceacting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.
In order to understand the results of another scientist's work, any scientist
who reads the report MUST understand the measurement system in which
the result is described. Otherwise the result is meaningless to him.
Answer:
The Force exerted on the student by crate will be 100 N.
Explanation:
As per the given Question student is trying to push the crate in right direction with the force of 100N.
And we know that, Newton's third law states that every action has equal and opposite reaction.
So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.
Answer:
256.3 N
Explanation:
Throughout the motion of the mass in the circular motion, the resultant of the Tension in the string and the weight of the body gives the net force (centripetal force) that is responsible for the acceleration of the mass in a circular motion.
At the top of the vertical circle of the motion of the mass, the tension is directed downwards towards the centre of the circle and the weight also is directed downwards towards the earth.
Net force = ma = T + W
ma = T + mg
But a = (v²/r) for circular motion,
(mv²)/r = T + mg
m = 2.31 kg
v = 7.77 m/s
r = 0.500 m
g = acceleration due to gravity = 9.8 m/s²
(2.31×7.77²)/0.5 = T + (2.31×9.8)
278.923 = T + 22.638
T = 278.923 - 22.638
T = 256.285 N = 256.3 N
Hope this Helps!!!
Answer:
and t = 0.5 s
Explanation:
Given that,
Mass of the object, m = 90 gram = 0.09 kg
Diameter of the circle, d = 2.56 m
Radius, r = 1.28 m
Speed, v = 16 m/s
We need to find the object acceleration. On the circular path, acceleration is given by :
So, the object's acceleration is 
.
Let t is time it will take to complete the around. Speed is given by :
So, time to cover one complete round is 0.5 s.
