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goblinko [34]
3 years ago
11

Two ice skaters hold hands and rotate, making one revolution in 2.87 s. Their masses are 59.0 kg and 73.0 kg, and they are separ

ated by 1.10 m. Find the angular momentum of the system about their center of mass. If the skaters pull towards each other and decrease their separation to 0.60 m, what is the new period of rotation about the center of mass?
Physics
1 answer:
pychu [463]3 years ago
7 0

Answer:

86.43

25.72

Explanation:

Location of center of mass from 59 Kg

r_1=\frac {xm_2}{m1+m2}=\frac {1.1*73}{59+73}= 0.608333m

Location of center of mass from 73 Kg

r_2=\frac {xm_1}{m1+m2}=\ frac {1.1*59}{59+73}= 0.491667m

Momentum of inertia

I=m1r_1^{2}+m2r_2^{2}=59*0.608333^{2}+73*0.491667^{2}=21.8341  +17.64674=39.48083  Kgm^{2}

Angular moment

L=I\omega=I(\frac {2\pi}{T})=39.48083(\frac {2*\pi}{2.87 s})=86.43393Js

(b)

When separation is 0.6 m

Location of centre of mass from 59 Kg

r_1=\frac {xm_2}{m1+m2}=\frac {0.6*73}{59+73}= 0.331818 m

Location of centre of mass from 73 Kg

r_2=\frac {xm_1}{m1+m2}=\ frac {0.6*59}{59+73}= 0.268182 m

Momentum of intertia

I=m1r_1^{2}+m2r_2^{2}=59*0.331818^{2}+73*0.268182^{2}=6.496095 + 5.250269=11.74636 Kgm^{2}

Angular moment

L=I\omega=I(\frac {2\pi}{T})=11.74636(\frac {2*\pi}{2.87 s})=25.71588 Js

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Par 1/2
BaLLatris [955]

part 1

mass = ρ x V

mass = 1739 kg/m³ x 3.8 km³ = 6608.2 kg

PE (potential energy)= mgh

PE = 6608.2 kg x 9.81 x 403

PE = 2.61 x 10⁷ J

part 2

megaton of TNT (Mt) =4.2 x 10¹⁵ J

convert PE to Mt:

2.61 x 10⁷ J : 4.2 x 10¹⁵ J = 6.21 x 10⁻⁹ Mt

4 0
2 years ago
D the element in blue square has a full outer shell, due to it’s location on the periodic table, so it will not react with other
Juliette [100K]
The correct response that will be used to describe this particular element would be the third option, since all of the other options are incorrect and apply to different elements in their groups. The element is a metal and will react with a non metal.






5 0
3 years ago
A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
barxatty [35]

Answer:

Velocity = 3.25[m/s]

Explanation:

This problem can be solved if we use the Bernoulli equation: In the attached image we can see the conditions of the water inside the container.

In point 1, (surface of the water) we have the atmospheric pressure and at point 2 the water is coming out also at atmospheric pressure, therefore this members in the Bernoulli equation could be cancelled.

The velocity in the point 1 is zero because we have this conditional statement "The water surface drops very slowly and its speed is approximately zero"

h2 is located at point 2 and it will be zero.

(P_{1} +\frac{v_{1}^{2} }{2g} +h_{1} )=(P_{2} +\frac{v_{2}^{2} }{2g} +h_{2} )\\P_{1} =P_{2} \\v_{1}=0\\h_{2} =0\\v_{2}=\sqrt{0.54*9.81*2}\\v_{2}=3.25[m/s]

4 0
3 years ago
A 5 N force is applied to a 3 kg ball to change its velocity from 9 m/s to 3 m/s. What is the impulse on the ball ?
nika2105 [10]
So, first the formula of Impulse is
I = force * time
We have force but no time.
Then, find time.
Next find acceleration,
F = mass * acceleration
5 = 3 * a
1.67 m/s^2
Next find time,
Acceleration = change in velocity / time
Change in velocity is velocity final - velocity initial
1.67 = 3 - 9 / time
Time = 3.6 s (round to 2 s.f.)
Lastly,
Impulse = force * time
Impulse = 5 * 3.6
Impulse is 18 Ns
3 0
2 years ago
Substitute the value 26.7 (or the exact value of 80/3) for x in the first of the original equation (x + y = 40) to find the valu
Tatiana [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the value of  y = 13.3

Explanation:

From the question we are told that

       The equation is  (x + y = 40)

        The first value of x is  x_1 =  26.7

        The second equation is  (0.75x + 1.5y = 40)

So  substituting x_1

     26.7 + y  =  40

=>   y = 13.3

Now substituting y and  x_1 into second equation

       0.75(26.7) +  (1.5* 13.3) =  40

 =>  40 = 40

So  y = 13.3

         

4 0
3 years ago
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