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andrew-mc [135]
3 years ago
9

3 a There is a thin layer of water between the blade and the ice. Suggest how this affects friction .​

Physics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

The water acts like a lubricant therefore has a smooth motion over the ice.

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Your odometer of your car says 54 123 miles when you start your trip, your watch says 9 45 AM When you get to your
strojnjashka [21]

Answer:

27 mph

Explanation:

9:45 to 11:45 = 2 hours

odometer says you traveled 54 miles in 2 hours or 27 mph

5 0
3 years ago
Light, dry snow is called powder. Skiing on a powder day is different than skiing on a day when the snow is wet and heavy. When
kramer

Answer:

Explanation:

Given:

- Acceleration a_dry = 0.4*a_wet

- initial velocity V_i

Find:

By how much does time taken to stop of dry snow differ from time taken to stop on wet snow?

Solution:

- Time taken to stop on wet snow t_wet:

                            V_f = V_i + a_wet * t_wet

                             t_wet = - a_wet / V_i

- Time taken to stop on wet snow t_wet:

                             V_f = V_i + a_dry * t_dry

                             t_dry = - a_dry / V_i

- Difference in t_wet and t_dry:

                             t_dry - t_wet =  - a_dry / V_i  + a_wet / V_i

                             dt = (a_wet - a_dry) / V_i

                             dt = (a_wet - 0.4*a_wet) V_i

                             dt = 0.6*a_wet / V_i

3 0
3 years ago
This is on series circuit- im stuck ong.
Thepotemich [5.8K]

Answer:

figure out what the letter mean , the figure how it's worth

5 0
3 years ago
A Pitot-static tube is mounted on a 2.5 cm pipe where oil (???? = 860 kg/m3, ???? = 0.0103 kg/m·s) is flowing. The Pitot tube is
emmasim [6.3K]

Answer:

\dot{V}=0.0733 \,m^3.s^{-1}

Explanation:

Given:

density, \rho=860\,kg.m^{-3}

diameter of the pipe, d=2.5\times 10^{-2}m

pressure difference, \Delta P=95.8\times 10^{5}\,Pa

In case of  pitot tube, the velocity is given by:

v=\sqrt{\frac{2.\Delta P}{\rho} }

v=\sqrt{\frac{2\times 95.8\times 10^{5}}{860} }

v=149.26\,m.s^{-1}

Now we know that volumetric flow rate is given as:

\dot{V}=a.v

where :

a= cross sectional area of the pipe

v= velocity of flow

\dot{V}=(\pi\times \frac{(2.5\times 10^{-2})^2}{4} ) \times 149.26

\dot{V}=0.0733 \,m^3.s^{-1}

4 0
3 years ago
How does the behavior of oobleck change as you increase the force
SIZIF [17.4K]
Hope this helps
If u hit oobleck hard it is a solid and when you pick it up and let it fall of your hand it turns into a liquid
8 0
3 years ago
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