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2 years ago

13

URGENTLY NEED HELP!!!!!!

1 answer:

Sav [38]2 years ago

6 0

Answer:

False.

Explanation:

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Why don't you hear a sound when you move your hand back and fourth through the air

inessss [21]

Your hand is not capable of moving fast enough for sound to come out of it.

3 0

3 years ago

Read 2 more answers

The speed of a projectile when it reaches its maximum height is 0.58 times its speed when it is at half its maximum height. What

Ne4ueva [31]

Speed of the projectile at its maximum height is only along horizontal direction

so at highest point

$v_1 = v_x$

now when he is at half of the maximum height the speed will be in x and y direction both

$v_2 = \sqrt{v_y^2 + v_x^2}$

here it is given that

$v_1 = 0.58 v_2$

$v_x = 0.58\sqrt{v_x^2 + v_y^2}$

$2.97 v_x^2 = v_x^2 + v_y^2$

$1.97 v_x^2 = v_y^2$

also we know that

$v_y^2 = v_{iy}^2 - 2 g \frac{H}{2}$

here we know that maximum height is given as

$H = \frac{v_{iy}^2}{2g}$

$v_y^2 = v_{iy}^2 - 2 g\frac{v_{iy}^2}{4g}$

$v_y^2 = \frac{v_{iy}^2}{2}$

now from above

$1.97 v_x^2 = \frac{v_{iy}^2}{2}$

$1.98 v_x = v_{iy}$

also we know that angle of projection is

$tan\theta = \frac{v_{iy}}{v_x}$

$tan\theta = \frac{1.98v_x}{v_x}$

so angle is

$\theta = tan^{-1} 1.98$

$\theta = 63.3 degree$

6 0

3 years ago

Two equal mass carts approach each other with velocities equal in magnitude but opposite in direction. Friction can be neglected

Viefleur [7K]

Answer:

0

Explanation:

Since momentum is given by:

$\vec{p}=m.\vec{v}$

Therefore momentum is a vector quantity in the direction of velocity.

Inelastic collision is the type of collision in which the masses combine after collision and start moving in the direction of the greater momentum but here in this case we have the momentum equal and opposite in direction.

<u>This case can be described mathematically as:</u>

$m_1.\vec{v_1}=m_2.\vec{v_2}$

since the mass and velocity are equal:

$m.\vec{v}=m.\vec{v}$

net momentum:

$p_{net}=0$

7 0

3 years ago

A positively charged rod is brought close to one end of an uncharged metal rod but does not actually touch it. What type of char

svlad2 [7]

Answer:

The end of the neutral rod which is the closest part to the charged rod would acquire a negative charge.

Explanation:

One of the rods is positively charged and one of them is neutral.

And the important part is that <u>they do not touch one another</u>, but get close to each other.

In this case, the end of the neutral rod which is the closest part to the charged rod would acquire a negative charge. This is because of the Coulomb's Law. The opposite charges exert an attractive force to each other. The positive charges attract the negative charges on the neutral rod.

7 0

3 years ago

A car moves at speed v across a bridge made in the shape of a circular arc of radius r. (a) Find an expression for the normal fo

inna [77]

Answer:

(a) FN = m (g - $\frac{v^{2} }{r}$ )

(b) vmin = 17.146 m/s

Explanation:

The radius of the arc is

r = 30m

The normal force acting on the car form the highest point is

FN = m (g - $\frac{v^{2} }{r}$ )

If the normal force become 0 we have

m (g - $\frac{v^{2} }{r}$ ) = 0

or

g - $\frac{v^{2} }{r}$ = 0

This way, when FN = 0, then v = vmin, so

g - $\frac{vmin^{2} }{r}$ = 0

vmin = $\sqrt[.]{g*r}$ = $\sqrt[.]{9.8 m/s^{2} * 30m } = 17.146 m/s$

4 0

3 years ago