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devlian [24]
3 years ago
6

Which elements have similar behavior? barium silicon aluminum strontium osmium beryllium

Physics
2 answers:
tresset_1 [31]3 years ago
8 0
Which elements have similar behavior? 
Barium, strontium, beryllium. 

Ilya [14]3 years ago
3 0

<u>Answer:</u> The elements which have similar behavior are Barium, strontium and beryllium.

<u>Explanation:</u>

Periodic table is divided into 7 periods and 18 groups.

The elements belonging to the same group will show chemical properties. Groups are the vertical columns in the periodic table.

From the given options:

Barium, strontium and beryllium, all belong to the group 2.

Silicon belong to group 14.

Aluminium belong to group 13 and Osmium belong to group 8.

Hence, the elements which have similar behavior are Barium, strontium and beryllium.

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Car 2 is travelling in a much higher speed than Car 1.But they are travelling or meeting in the same acceleration

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A machine puts out 6,000 J of work. To produce that much work the machine
topjm [15]

Answer:

Efficiency of the machine = 75%

Explanation:

Given:

Input work = 8,000 J

Output work = 6,000 J

Find:

Efficiency of the machine

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Efficiency of the machine = [Output work / Input work]100

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Efficiency of the machine = 75%

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3 years ago
How many "one-sixth parts are needed to make one<br>whole?​
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6 one-sixth parts are needed to make a whole.
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3 years ago
Consider two identical objects released from rest high above the surface of Earth. (Neglect air resistance for this question.)
Nadusha1986 [10]

The question is missing its alternatives. Here is the complete question.

Consider two identical objects released from rest high above the surface of Earth. In Case 1, the object is released from a height above the surface of Earth equal to 1 Earth radius, and we measure its kinetic energy just before it hits the Earth to be K1. In Case 2, the obejct is released from a height above the surface of Earth equal to 2 Earth radii and its kinetic energy just before it hits is K2.

1. Compare the kinetic energy of the two objects just before they hit the surface of the earth.

a) K2 = 2K1; b) K2 = 4K; c) K2 = (4/3)K1; d) K2 = (3/2)K1;

Answer: C) K2 = (4/3)K1

Explanation: As it is related to the gravity of the Earth, the potencial energy is: U(r)= - \frac{G.Me.m}{r} + U₀

In this case, U₀=0, G is the universal gravitational constant, Me is the mass of Earth, m is the mass of the object and r is the distance between the center of the Earth and the object.

The potencial energy of an object of mass m on the surface of the Earth is:

Usurface = - \frac{G.Me.m}{Re}

The potencial energy of the object in Case 1 is

U1 = - \frac{G.Me.m}{2Re}

For the Case 2:

U2 = - \frac{G.Me.m}{3Re}

The potencial change in Case 1:

ΔU1 = - G.Me.m.(\frac{1}{Re}-\frac{1}{2Re}) = - \frac{1}{2}\frac{G.Me.m}{Re}

For Case 2:

ΔU2 = - G.Me.m(\frac{1}{Re}-\frac{1}{3Re}) = - \frac{2}{3}\frac{G.Me.m}{Re}

Comparing ΔK1 and ΔK2 equals comparing ΔU1 and ΔU2:

Δ\frac{U2}{U1} = (-2/3)(-1/2) = 4/3

So, comparing kinetic energies, K2 is 4/3 of K1.

5 0
4 years ago
The value of gravitational acceleration of a body on Earth is 9.8 meters/second2. The gravitational potential energy for a 1.00
solong [7]
PE = mgh₁ - mgh₂= 12.5J

h₁ = ?
h₂ = 0

h₁ = PE / mg = 12.5 / 9.8


6 0
3 years ago
Read 2 more answers
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