All categories

3 years ago

What is -6/-3 simplified

Mathematics

1 answer:

Setler [38]3 years ago

3 0

Answer:

Step-by-step explanation:

3 goes into 6, 2 times and negative on negative is positive

You might be interested in

Solve for q. Write your answer as “q=___”

wolverine [178]

Answer:

7q-46= 3q +6

7q-3q = 6+ 46

4q= 52

4q/4= 52/4

q= 13

3 0

3 years ago

Read 2 more answers

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago

Helppp meeee plssss with this pls

Darina [25.2K]

It’s the letter “B” I think

8 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle is four times the length of one of the legs. The length of the other leg is 1500⎯⎯⎯⎯⎯⎯⎯⎯√ fee

Mrac [35]

Answer:

Step-by-step explanation:

So this is just playing with the pythagorean theorem

a^2 + b^2 = c^2 with a and b as legs and c as the hypotenuse.

Let's say a is equal to 1500 so then c is 4 times b

1500^2 + b^2 = (4b)^2 Now we just treat this like a normal algebraic expression

2,250,000 = 16b^2 - b^2

2,250,000 = 15b^2

150,000 = b^2

sqrt(150,000) = b

100sqrt(15) = b

You can check this now.

1500^2 + sqrt(150,000)^2 = c^2

sqrt(2,250,000 + 150,000) = c

sqrt(2,400,000) = c

400sqrt(15) = c Which fits the requirement of c = 4b

7 0

3 years ago

Write the following numbers in order from least to greatest,

PIT_PIT [208]

Answer: D

Step-by-step explanation:

Look at the exponents first and order them from least to greatest

5 0

3 years ago