All categories

3 years ago

If g(x)= 3x-1 solve for x when g(x)=-20.

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

Good evening

Answer:

$x=\frac{-19}{3}$

Step-by-step explanation:

g(x) = -20

⇔

3x-1 = -20

⇔

3x = -20 + 1

⇔

3x = -19

⇔

x = -19/3

____________________

You might be interested in

PLZ HELP ill GIVE BRAINIESt!!!!20 Points

jekas [21]

A. more homework better scores
b. about 60 score
c. standard score

7 0

3 years ago

Read 2 more answers

The parents club wants to sell buttons to raise money for the local community center sports program. The buttons cost 60 cents e

astraxan [27]

Their profit made will be 4,420

This is because 0.60 x 1300 is 780

And the amount they will make by selling is $5200, because 1300 x 4

So we will do 5200 - 780, and that is the profit made- $4,420

3 0

4 years ago

Read 2 more answers

Organize the given volumes of cubes as either a perfect cube or not-perfect cube.

stiks02 [169]

Answer:

343m3,8m3,1000m3 for Perfect squares

300m3,9m3,900m3 for Not-perfect squares

Step-by-step explanation:

Did an assignment on edge

4 0

3 years ago

The annual expenditure of the US federal government is approximately 4 44 trillion dollars. If a one dollar bill is 0 . 0 0 0 1

kaheart [24]

Answer:

<em>A stack of 4 trillion one dollar bills will be $4\times 10^8$ meters.</em>

Step-by-step explanation:

The annual expenditure of the US federal government is approximately 4 trillion dollars.

We know, 1 trillion dollars = 10¹² dollars.

So, 4 trillion dollars $=(4\times 10^1^2)$ dollars.

Each one dollar bill is 0.0001 meters thick.

So, the total height of the stack of 4 trillion one dollar bills will be.....

$[0.0001\times(4\times 10^1^2)]meters\\ \\ =[10^-^4\times(4\times 10^1^2)]meters\\ \\ =(4\times 10^8) meters$

6 0

3 years ago

The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse

diamong [38]

Answer: The answer is cosine of that acute angle.

Step-by-step explanation: We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

$\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.$

Thus, the ratio is cosine of the acute angle.

7 0

3 years ago