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2 years ago

15

What is the sign of the product? (0.5)(–0.5)(3.2)(–7.9)(–2.4)

1 answer:

Harlamova29_29 [7]2 years ago

5 0

There are three negative signs so the product will be a negative.
hope this helps

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Helpppp<br> Solve for x.

SVEN [57.7K]

Answer:

x = 28.744

Step-by-step explanation:

Seeing as this is a right triangle, and you're given an angle, an unknown measurement to the opposite side, and the measure of the adjacent side. You can use trig functions. In this case, tangent, because you are given the opposite and adjacent, and tangent covers opposite/adjacent.

Tan(32)=x/46

Tan(32)46=x

28.744=x

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1 year ago

For what value of k does the equation have no solution? kx - 4 = 5x + 8

baherus [9]

Answer:

Your answer is: k = 5+12/x

Isolate the variable by dividing each side by factors that don't contain the variable.

Step-by-step explanation:

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3 years ago

Find (fog)(x) when f(x)=x^2-7x+12 and g(x)=7/x^2-16

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2 years ago

Solue for X <br>will give brainliest <br>don't put links or will be reported

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2 years ago

Read 2 more answers

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5$

For RT:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1$

For ST:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4$

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

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2 years ago