All categories

2 years ago

Louis age is three years more than twice the age of Sánchez . The sun of their ages is 39. How old are Sánchez and Louis ?

Mathematics

1 answer:

Vinvika [58]2 years ago

5 0

Answer:

Sanchez- 42

Louis- 40

Step-by-step explanation:

hope this helps

You might be interested in

Can y’all help me on question 19?!

m_a_m_a [10]

Answer: 178.31

Step-by-step explanation: subtract 574.54 by 396.23

8 0

3 years ago

Read 2 more answers

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

avanturin [10]

Thanks, this app has helped me a lot.

5 0

2 years ago

Read 2 more answers

Please help!!!! will mark brainlest

fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

Area of rectangle=50 in²

Next, calculate the area of the trapezoid:

Area of trapezoid= $\frac{h(b_{1} +b_{2}) }{2}$

h=10 in-6 in

h=4 in

$b_{1} =15 in$

$b_{2} =15 in-5 in$

$b_{2} =10 in$

Area of trapezoid= $\frac{4in(7 in+10in)}{2}$

Area of trapezoid= $\frac{4(17in^{2}) }{2}$

Area of trapezoid= $\frac{68in^{2} }{2}$

Area of trapezoid= $34in^{2}$

Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²

3 0

2 years ago

What is the form of the two squares identity?

zvonat [6]

Answer:

Step-by-step explanation:

Consider all options:

A. False, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ab-cd)^2+(ac+bd)^2=a^2b^2-2abcd+c^2d^2+a^2c^2+2abcd+b^2d^2=\\ =a^2b^2+c^2d^2+a^2c^2+b^2d^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2\neq a^2b^2+c^2d^2+a^2c^2+b^2d^2$

B. False, because

$(a^2-b^2)(c^2+d^2)=a^2c^2+a^2d^2-b^2c^2-b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2-b^2c^2-b^2d^2\neq a^2c^2+b^2d^2+a^2d^2+b^2c^2$

C. False, because

$(a^2+b^2)(c^2-d^2)=a^2c^2-a^2d^2+b^2c^2-b^2d^2\\ \\(ac+bd)^2-(ad+bc)^2=a^2c^2+2abcd+b^2d^2-a^2d^2-2abcd-b^2c^2=\\=a^2c^2+b^2d^2-a^2d^2-b^2c^2\\ \\a^2c^2-a^2d^2+b^2c^2-b^2d^2\neq a^2c^2+b^2d^2-a^2d^2-b^2c^2$

D. True, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2= a^2c^2+b^2d^2+a^2d^2+b^2c^2$

6 0

3 years ago

Sam bought brushes for $8, a palette for $5, and oil paints for $15. He paid $29.82 in all. What sales-tax rate did Sam pay?

Tpy6a [65]

First step is to add all the expenses of Sam bought. The sum is equal to 8 + 5 + 15 equal to $28. With the addition of the tax, the tax amounts to a total of $1.82. This means the tax, imposed is $1.82/$28 *100% equal to 6.5 percent

3 0

3 years ago

Read 2 more answers