That's already rounded to the nearest tenth
The factors are
(x-y)(x-y)
or
(x-y)^2
Explanation:
We need to factor the trinomial
x^2-2xy+y^2
The factors of x^2 = (x)(x)
The factors of y^2 = (y)(y)
Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same. Since the first sign is negative both signs must be negative.
The factors are
(x-y)(x-y)
or
(x-y)^2
Check by FOIL
Firsts (x)(x) = x^2
Outers (x)(-y) = -xy
Inners (-y)(x) = -xy
Lasts (-y)(-y) = y^2
combine the middle terms
(-xy)+(-xy) = -2xy
<span>x^2-2xy+y^2</span>
The answer would be 27/14
Answer:
Second option: B and C
Step-by-step explanation:
A is the product of 4x and -2x: A=(4x)(-2x)→A=-8x^2 (x^2)
B is the product of 4x and 3: B=(4x)(3)→B=12x (x^1)
C is the product of 1 and -2x: C=(1)(-2x)→C=-2x (x^1)
D is the product of 1 and 3: D=(1)(3)→D=3 (constant)
Then, the like terms are B and C