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mel-nik [20]
3 years ago
8

Please answer correctly Option d is x=10 the picture was to big to include that option

Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

The answer is x = 10.

Step-by-step explanation:

Use the pythagorean theorem.  A would be 6, B would be 8, and C would be solved by the product of that.

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According to the line plot, how much more is the total weight of the 1/2 of a pound dog toys than the weight of the 5/8 of a pou
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You didn’t attach the line plot but I’ll do my best.

1 pound = 16 ounces

It says of a pound dog toys, meaning that we will have to do multiplication:

1/2 * 1 pound

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= 10

Next, find the difference:

10 - 8 = 2

The total weight of 5/8 of a pound of dog toys is 2 ounces greater than 1/2 of a pound of dog toys.


Also, the last bit of the question is worded incorrectly. 5/8 > 1/2 right off the bat. I’m not sure who designed the question but I think you should let them know since it would likely confuse individuals who encounter this question. Hope this helps!
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Step-by-step explanation:

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1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang
Mandarinka [93]
1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is \frac{ \sqrt{3} }{2} a

2. if a a=25 ft, then the height is \frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7 (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}

so the total area of the roof is \frac{ \sqrt{3} }{2} a^{2} +3al

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al


5. so the area now is \frac{ \sqrt{3} }{2} a^{2} +2al

6. now a=25 and l=2a=50

Area=\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2}  (\frac{ \sqrt{3} }{2} +4)=625*4.866

=3041.3 (ft squared)

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Answer:

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