Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.
The grew greatest price that is in both lists is $6.
How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.
Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
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Hope this helps you
C is the answer I pretty sure of it
There is nothing here for anyone to work off, If you have a picture or screenshot that would be very nice!
Answer: 
Step-by-step explanation:
Given : Number of choices for novels = 4
Number of choices for plays = 6
Number of choices for poetry books = 5
Number of choices for nonfiction books = 5
Total books =4+6+5+5=20
If he wants to include all 4 novels, then the number of books left to select = 9-4=5
Remaining choices for books = 20-4=16
Number of combinations of n things taking r at a time : 
Then, the number of different reading schedules are possible :_
Hence, the required answer is .
