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scoundrel [369]

4 years ago

7

Daniels print shop purchased a new printer for $35,000. Each year it depreciates at rate of 5%. How much will the printer be wor

th in 8 years?

1 answer:

Savatey [412]4 years ago

7 0

Ab^x
a: initial value
b: value remaining after depreciation per year (in percentage)
x: number of years that have passed

35000(0.95)^8= 23219.7151

Round to the nearest hundredth value:
About $23219.72

Let me know if you have any questions :)

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Can I get help please

WITCHER [35]

Answer:

sorry you cant get help but you can help me!

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Step-by-step explanation:

8 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago

WILL GIVE BRAINLEST PLZZZZ HELP (06.04) What is the value of Fraction 1 over 2x3 + 3.4y when x = 2 and y = 5?

Jet001 [13]

Answer:

21

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help me !! And show your work

valkas [14]

-24+12d=2d-6+22
-24+12d=2d+16
-24+12d+24=2d+16+24
12d=2d+40
12d-2d=2d+40-2d
10d=40
10d/10=40/10
D=4

6 0

3 years ago

Which name best describes the polygon with vertices (0, 0), (4, 8), (12, 8), and (16, 0)? A) Triangle C) Trapezoid B) Square D)

stellarik [79]

Answer:

C) Trapezoid

Step-by-step explanation:

Given

$A = (0,0)$

$B = (4,8)$

$C = (12,8)$

$D=(16,0)$

Required

The possible shape

The above are 4 vertices.

Hence, the shape cannot be

(a) Triangle ---- it has 3 vertices

(b) Pentagon ---- it has 5 vertices

Calculate distance AB using distance formula

$AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$A = (0,0)$

$B = (4,8)$

$AB = \sqrt{(0 - 4)^2 + (0 - 8)^2$

$AB = \sqrt{( - 4)^2 + ( - 8)^2$

$AB = \sqrt{16+64$

$AB = \sqrt{80$

$AB = 8.94$

Calculate distance BC using distance formula

$BC = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$B = (4,8)$

$C = (12,8)$

$BC = \sqrt{(4 - 12)^2 + (8 - 8)^2$

$BC = \sqrt{(-8)^2 + (0)^2$

$BC = \sqrt{64 +0$

$BC = \sqrt{64$

$BC = 8$

Since

$AB \ne BC$

<em>Then, the polygon is not a square</em>

<em></em>

<em>The last available option is (c) trapezoid</em>

4 0

3 years ago

Read 2 more answers