The area of the circle A and B is 86.54 inches and 124.62 mm
According to the statement
we have given that the radius of the circle A and b and we have to find the area of the given circle.
So, we know that the
The area enclosed by a circle of radius r is πr².
So, For area of the circle
For condition A :
diameter = 10.5 inches
then radius = 5.25
Area = πr²
Area = 3.14*27.56
Area = 86.54 inches
Now, For condition B :
radius = 6.3 mm
Area = πr²
Area = 3.14*39.69
Area = 124.62mm
So, The area of the circle A and B is 86.54 inches and 124.62 mm
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The answer is 40°
i will tell you how,
Total angle sum of any triangle is 180°
∠A + ∠B + ∠E = 180°
70° + 80° + ∠E = 180°
solve for ∠E
∠E = 30°
Now solve use ∠BDE,
∠B + ∠D + ∠E = 180°
20° + 90° + 30° + x = 180° (in triangle DEB, ∠E = 30 + x ) (∠D is 90°)
solve for x
there fore, x = 40°
Answer:
See below ~
Step-by-step explanation:
<u>Finding x-intercept</u>
- Take y = 0
- 2x - 5(0) = 10
- 2x = 10
- x = 5
- x-intercept is at (5, 0)
<u>Finding y-intercept</u>
- Take x = 0
- 2(0) - 5y = 10
- -5y = 10
- y = -2
- y-intercept is at (0, -2)
<u>Graph (with points marked)</u>
Answer:
[1] = 6
x = -3/2 is the root
Step-by-step explanation:
A perfect square trinomial is of the form ...
(a + b)² = a² +2ab +b²
You have ...
- a²=16w² ⇒ a = 4w
- b² = 36 ⇒ b = 6
- 2ab = 2(4w)(6) = 48w
Then the factorization is ...
16w² +48w +36 = (4w +6)²
This will be zero when x = -6/4 = -3/2.
