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iVinArrow [24]
2 years ago
6

Question 23 (3 points)

Chemistry
1 answer:
Mice21 [21]2 years ago
3 0

Answer:

<h2>The answer is 3.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of aluminum = 8.1 g

density = 2.7 g/mL

It's volume is

volume =  \frac{8.1}{2.7}  \\

We have the final answer as

<h3>3.0 mL</h3>

Hope this helps you

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Consider the reaction and its equilibrium constant at 25.0 ∘C :
olga55 [171]

Since Qp>Kp , the reaction is not at equilibrium.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant shows the extent to which reactants are converted into products.

Now we have to obtain the Qp as follows;

Qp =[CH3OH]/[CO] [H2]^2

Qp = 0.265/(0.265) (0.265)^2

Qp = 14.2

Now we know that Kp = 6.09×10−3, Since Qp>Kp , the reaction is not at equilibrium.

Learn more about equilibrium constant:brainly.com/question/10038290

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5 0
1 year ago
There are over 100 elements, but only
elena-14-01-66 [18.8K]

Answer:

Symbol_Element

He_Helium

Li_Lithium

Be_Beryllium

B_Boron

C_Carbon

N_Nitrogen

O_Oxygen

F_Fluorine

Ne_Neon

Na_Sodium

Mg_Magnesium

Al_Aluminum

Si_Silicon

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S_Sulfur

Cl_Chlorine

Ar_Argon

K_Potassium

Ca_Calcium

Sc_Scandium

Ti_Titanium

V_Vanadium

Cr_Chromium

Mn_Manganese

Fe_Iron

Co_Cobalt

Ni_Nickel

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Zn_Zinc

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6 0
3 years ago
What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184
pav-90 [236]

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

525 J = m × 12.552 j/g

m =  525 J/ 12.552 j/g

m = 41.8 g

4 0
3 years ago
What are two examples of homogeneous<br>​
Andrei [34K]

Answer:

two examples are blood and soapy water.

Explanation:

7 0
2 years ago
Which corresponds to a pressure of 1.23 atm? 8.73 mmHg 9.23 mmHg 125 mmHg 935 mmHg
rosijanka [135]
(935mmHg/760mmHg)=1.23 atm
5 0
3 years ago
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