Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.
While,
Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.
Percentage Yield is Calculated as,
%age Yield = Actual Yield / Theoretical Yield × 100
Data Given:
Actual Yield = 0.104 g
Theoretical Yield = 0.110 g
Putting Values,
%age Yield = 0.104 g / 0.110 g × 100
%age Yield = 94.54 %
Answer:
6.53g of K₂SO₄
Explanation:
Formula of the compound is K₂SO₄
Given parameters:
Volume of K₂SO₄ = 250mL = 250 x 10⁻³L
= 0.25L
Concentration of K₂SO₄ = 0.15M or 0. 15mol/L
Unknown:
Mass of K₂SO₄ =?
Methods:
We use the mole concept to solve this kind of problem.
>>First, we find the number of moles using the expression below:
Number of moles= concentration x volume
Solving for number of moles:
Number of moles = 0.25 x 01.5
= 0.0375mole
>>Secondly, we use the number of moles to find the mass of K₂SO₄ needed. This can be obtained using the expression below:
Mass(g) = number of moles x molar mass
Solving:
To find the molar mass of K₂SO₄, we must know the atomic mass of each element in the compound. This can be obtained using the periodic table.
For:
K = 39g
S = 32g
O = 16g
Molar mass of K₂SO₄ = (39x2) + 32 + (16x4)
= 78 +32 + 64
= 174g/mol
Using the expression:
Mass(g) = number of moles x molar mass
Mass of K₂SO₄ = 0.0375 x 174 = 6.53g
Answer:
Explanation:
Your B-L Acid is a proton (Hydrogen, H+) donor, and your B-L base is a proton acceptor. This means that the base will take a hydrogen from your acid. NO2- is a B-L base, and you can tell it is a base by the negative charge it possesses. This means that it has a lone pair that wants to grab one of the hydrogens from NH4+, the B-L acid. In scientific words, the NO2- is a nucleophile and NH4+ is an electrophile. The result of NO2- grabbing that hydrogen from NH4+ is that NO2- becomes HNO2 (your conjugate acid) and and NH4+ becomes NH3 (you conjugate base). Basically, any time a B-L acid loses a proton, its equal product will be its conjugate base, and any time a B-L base gains a proton, its equal product will be its conjugate acid.
I hope this helped explain the concept behind Bronsted-Lowry acids and bases! Good luck with your class and please don't forget to give a positive rating! :-)
Assuming the kind of vibration you are talking about is the kind where you stretch the rubber band between two points and then "twang" it, then the answer is fairly complex. What happens when you cause the vibrations to start is you make something called a "standing wave". In a standing wave, each particle in the rubber band has a certain amount of energy which causes it to move backwards and forwards, the particles with more energy have a larger "amplitude" (how much they move), and of course the particles with less energy have a smaller amplitude. Now a standing wave has two main components: The amplitude, and the frequency. The amplitude of the whole wave refers to the largest amplitude any particles has. The frequency refers to how often it takes for one of the particles to move between the two furthest away points it can be.
To compare rubber bands, you must remember to keep certain things constant. If you're looking at their vibrations, the amount of energy you use to "twang" the rubber band should be the same each time you twang it (which is the same as applying the same force each time you twang it).
A larger rubber band has more area over which to spread the energy, as well as it has more mass for the energy to move, so the vibrations will have smaller amplitudes, and smaller frequencies, overall vibrating less and with smaller vibrations.