Answer: The volume occupied by 2.50 moles of
gas at STP is 56.0L
Explanation:
According to ideal gas equation:

P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 2.50
R = gas constant =
T =temperature =
(at STP)


Thus the volume occupied by 2.50 moles of
gas at STP is 56.0L
Answer:
(a) Density of the air = 1.204 kg/m3
(b) Pressure = 93772 Pa or 0.703 mmHg
(c) Force needed to open the door = 15106 N
Explanation:
(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

First, we change the units of P to Pa and T to deg K:

Then we have

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

The choices can be found elsewhere and as follows:
<span>(1) substitution
(2) esterification
(3) addition
(4) fermentation
</span>
I believe the correct answer is option 3. The reaction CH2CH2 + H2 → CH3CH3 is an example of an addition reaction. It is a<span> </span>reaction<span> where two or more molecules combine to form a larger one. Hope this answers the question.</span>
Answer:
338.00 mL
Explanation:
The lead ions come from the salt Pb(NO₃)₂ and the iodide from the acid HI, so the balanced reaction is:
Pb(NO₃)₂(aq) + 2HI(aq) → PbI₂(s) + 2HNO₃(aq)
So, the stoichiometry is 1 mol of Pb(NO₃)₂ to 2 moles of HI, then:
1 mol of Pb(NO₃)------------------------------------ 2 moles of HI
0.600 mol of Pb(NO₃)₂--------------------------- x
By a simple direct three rule:
x = 1.200 mol of HI
The acid has concentration equal to 3.550 mol/L, the volume (V) is the number of moles divided by the molar concentration:
V = 1.200/3.550 = 0.338 L
V = 338.00 mL