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Kitty [74]
3 years ago
7

What is the pH of a solution with a concentration of 1.8 × 10-4 molar H3O+?

Chemistry
1 answer:
Andre45 [30]3 years ago
8 0
PH is defined as the negative log of Hydrogen ion concentration. Mathematically we can write this as:

pH=-log[H^{+}]=-log[H_{3}O]

We are given the concentration of H_{3}O. Using the value in formula, we get:

pH=-log[1.8*10^{-4}]=3.745

Therefore, the pH of the solution will be 3.745
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7 0
3 years ago
What is the concentration of H+ ions at a pH = 11?
natta225 [31]

Answer:

\huge 1 × {10}^{-11} \: \: M

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

Since we are finding the H+ ions we find the antilog of the pH

So we have

11 =  -  log({H}^{+})  \\ {H}^{+} =  {10}^{ - 11}

We have the final answer as

1 × {10}^{-11} \: \: M

Hope this helps you

6 0
2 years ago
How to tell if an equation is exothermic or endothermic?
levacccp [35]
The standard enthalpy change of a reaction is positive thus endothermic.

The standard enthalpy change of a reaction is negative thus exothermic.

Hope it helped!
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3 years ago
What are the two types of dichotomous keys. Which is easier to use?
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5 0
2 years ago
An ideal diatomic gas starting at room temperature T1 = 300 K and atmospheric pressure p1 = 1.0 atm is compressed adiabatically
tangare [24]

Answer:

The final temperature of the given ideal diatomic gas: <u>T₂ = 753.6 K</u>

Explanation:

Given: Atmospheric pressure: P = 1.0 atm

Initial Volume: V₁ , Final Volume: V₂ = V₁ (1/10)

⇒ V₁ / V₂ = 10

Initial Temperature: T₁ = 300 K, Final temperature: T₂ = ? K

 

For a diatomic ideal gas: γ =  7/5

For an adiabatic process:

V^{\gamma-1 }T = constant

V_{1}^{\gamma-1 }T_{1} = V_{2}^{\gamma-1 }T_{2}

\left [\frac{V_{1}}{V_{2}} \right ]^{\gamma-1 } = \frac{T_{2}}{T_{1}}

\left [10 \right ]^{\frac{7}{5}-1 } = \frac{T_{2}}{300 K}

\left [10 \right ]^{\frac{2}{5} } = \frac{T_{2}}{300 K}

2.512 = \frac{T_{2}}{300 K}

T_{2} = 753.6 K

<em><u>Therefore, the final temperature of the given ideal diatomic gas</u></em><em>:</em> T₂ = 753.6 K

8 0
3 years ago
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