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3 years ago

What is the pH of a solution with a concentration of 1.8 × 10-4 molar H3O+?

1 answer:

8 0

PH is defined as the negative log of Hydrogen ion concentration. Mathematically we can write this as:

$pH=-log[H^{+}]=-log[H_{3}O]$

We are given the concentration of $H_{3}O$ . Using the value in formula, we get:

$pH=-log[1.8*10^{-4}]=3.745$

Therefore, the pH of the solution will be 3.745

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If you observe with the microscope that a cell contains chloroplasts can you conclude that this is a plant cell?

shusha [124]

Obviously since plant cell contains chloroplasts.

8 0

3 years ago

(20 POINTS!!) please help me write a short reference page on chemical bonds (anything helps)

Shtirlitz [24]

Explanation:An ionic bond essentially donates an electron to the other atom participating in the bond, while electrons in a covalent bond are shared equally between the atoms. The only pure covalent bonds occur between identical atoms. ... Ionic bonds form between a metal and a nonmetal. Covalent bonds form between two nonmetals.

7 0

3 years ago

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.

Lady bird [3.3K]

Answer:

5.90, 11.8, 47.2

Explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴ $\text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{5.90 mol Mg atoms}$

$\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{11.8 mol Cl atoms}$

$\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_{4})_{2} \times \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_{4})_{2}} = \text{47.2 mol O atoms}$

∴ Mg, Cl, O = 5.90, 11.8, 47.2

4 0

3 years ago

In the equation below, identify the Brønsted-Lowry acid, the Brønsted-Lowry base, conjugate acid, conjugate base.

AnnyKZ [126]

Answer:

Explanation:

Your B-L Acid is a proton (Hydrogen, H+) donor, and your B-L base is a proton acceptor. This means that the base will take a hydrogen from your acid. NO2- is a B-L base, and you can tell it is a base by the negative charge it possesses. This means that it has a lone pair that wants to grab one of the hydrogens from NH4+, the B-L acid. In scientific words, the NO2- is a nucleophile and NH4+ is an electrophile. The result of NO2- grabbing that hydrogen from NH4+ is that NO2- becomes HNO2 (your conjugate acid) and and NH4+ becomes NH3 (you conjugate base). Basically, any time a B-L acid loses a proton, its equal product will be its conjugate base, and any time a B-L base gains a proton, its equal product will be its conjugate acid.

I hope this helped explain the concept behind Bronsted-Lowry acids and bases! Good luck with your class and please don't forget to give a positive rating! :-)

7 0

3 years ago

What is the frequency of a photon having an energy of 4.91 × 10–17 ? (c = 3.00 × 108 m/s, h = 6.63 × 10–34 J · s)

AlexFokin [52]

Answer:

The frequency of the photon is 7.41*10¹⁶ Hz

Explanation:

Planck states that light is made up of photons, whose energy is directly proportional to the frequency of radiation, according to a constant of proportionality, h, which is called Planck's constant. This is expressed by:

E = h*v

where E is the energy, h the Planck constant (whose value is 6.63*10⁻³⁴ J.s) and v the frequency (Hz or s⁻¹).

So the frequency will be:

$v=\frac{E}{h}$

Being E= 4.91*10⁻¹⁷ J and replacing:

$v=\frac{4.91*10^{-17} J}{6.63*10^{-34} J.s}$

You can get:

v= 7.41*10¹⁶ $\frac{1}{s}$ = 7.41*10¹⁶ Hz

The frequency of the photon is 7.41*10¹⁶ Hz

4 0

3 years ago