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zaharov [31]
3 years ago
9

55. Which Element has a larger radius- Rb or I?

Chemistry
1 answer:
Luden [163]3 years ago
5 0

Rb has larger radius.

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Explanation:

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If a wave is traveling at a steady speed and its frequency is
Nataly [62]

Answer:

If the frequency is doubled, the wavelength is only half as long.

Explanation:

Wave speed equals frequency*wavelength. So doubling the frequency must halve the wavelength in order for wave speed to remain the same.

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3 years ago
One mole of copper has a mass of 63.5 grams. Approximately how many atoms of copper are present in one mole of copper?
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What do we need to know about a molecule in order to carry out molarity calculations
professor190 [17]

Answer the type of cell

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7 0
3 years ago
"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Alex17521 [72]

Answer:

\boxed{\text{0.50 mol/L}}

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}

2. Solve for x

K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}

3. Calculate the equilibrium concentration of COF₂

c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}

Check:

\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}

OK.

5 0
4 years ago
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